Find how many times 10 seconds is in 2 minutes and 45 seconds (16 times) and then multiply that my 6 (96) Then find what half of 6 is to compensate for the leftover 5 seconds (Half of 10 - so therefore the remaining amount of cars will be half of 6) to get 99 cars.
This is the graph, the x and y intercept would be (0,0)
Step-by-step explanation:
x+5=36
or, x=36-5
or, x=31
The value of x=31
Call the number of courses ' C '.
Whatever it is, it will cost her [ 55 + 450C ].
How many courses can she get for $1,200 ?
55 + 450C = 1200
Subtract 55 from each side:
450C = 1145
Divide each side by 450 :
C = 1145 / 450 = 2.544...
She can only register for a whole number of courses, so<u> 2 </u>is the limit.
That will cost her (55 + 2x450) = (55 + 900) = $955
and she'll have $245 left over ... not enough for another course.
Answer:
n = 27
Step-by-step explanation:
168n is a multiple of 324
168(27) = 4536 is a multiple of 324
BRAINLIEST?
