I hope you meant, a cross between BbPp and BbPp, else for bbpp x bbpp, all the progeny will be bbpp.
We need to work out a Punnett square to determine the genotypes resulting from the cross between BbPp and BbPp. The dyhybrid cross results in 16 different genotypes, of which a few have the same phenotypes.
It can be seen that there are 4 different kinds of phenotypes present, in the ratio 9:3:3:1.
The mother's genotype can be either or
.
For X-linked recessive traits, males (XY) can either be affected or free from the disorder, they cannot be carriers. Females (XX), on the other hand, can be affected, unaffected, or be carriers.
The circled male child is free from the disorder () while the females are carriers (
).
The male inherited the healthy allele, , from the mother.
The female children inherit the affected allele from their father (who is affected for the disorder) and the other healthy allele from their mother.
This means that the mother cannot be affected for the disease. As it is, the pedigree points that all the children got their healthy alleles from their mother. This does not mean the mother has two healthy alleles though.
Thus, the possible genotype of the mother are and
.
More on pedigrees can be found here: brainly.com/question/2952835?referrer=searchResults
Answer:
Option 3,
Explanation:
In the process of cellular respiration, the sugar is oxidised to convert into carbon dioxide , water and energy molecule ATP (Adenosine Tri Phosphate)
If the above chemical reaction is represented mathematically it will be as follows -
The above reaction is a balanced chemical reaction representing cellular reaction
Thus, option 3 is correct