The data is qualitative (statement is incorrect)
The data is skewed right (statement is correct)
There were 31 people at the party (statement is correct)
There were children at the party (statement is incorrect)
The most common age of the attendees is 13 years old (statement incorrect - there is no way to tell that the most common age is 13 years old)
The majority of people at the party is less than 61 years old (statement correct)
The images to solve this problem is in the attachment.
Answer: 
= 671.0 N; 
= 300 N
Step-by-step explanation: From the image in the attachment and knowing that the box is in equilibrium, i.e., the "sum" of all the forces is 0, it is possible to conclude that:
= 
and = 
Using trigonometry, shown in the second attachment, the values for each force are:
sin 20° = 
= 
. sin(20)
= 735.0.913
= 671.0
cos 20° = 
= . cos (20)
= 735.0.408
= 300
The force of static friction is 671N and normal force is 300N
I would say P = w + 2, because their ages change over time but the difference between the ages will always be the same.
Rewrite s = 4 + sqrt(s+2) as s-4 = sqrt(s+2)
Square both sides: s^2 - 8s + 16 = s + 2
combine like terms: s^2 - 9s + 14 = 0
Factor this: (s-7)(s-2)=0
Solve for s: s={7, 2}
Term 11=a+10d
Here
a=10
d= 7-10= -3
Term 11;
=10+(10×-3)
=10+(-30)
= -20 is the answer
Thank you Hope it helps dear
