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2 years ago

14

Which statements must be true according to the histogram? Check all that apply.

2 answers:

Alisiya [41]2 years ago

8 0

The data is qualitative (statement is incorrect)
The data is skewed right (statement is correct)
There were 31 people at the party (statement is correct)
There were children at the party (statement is incorrect)
The most common age of the attendees is 13 years old (statement incorrect - there is no way to tell that the most common age is 13 years old)
The majority of people at the party is less than 61 years old (statement correct)

musickatia [10]2 years ago

7 0

Answer:

b,c,f

Step-by-step explanation:

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Pls help me on this k12 question.

andrew-mc [135]

Answer: The answer is A, 132 units

Step-by-step explanation:

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2 years ago

What number is in the tenth's place? 41.53

zysi [14]

Answer: The number in the tenth's place is <u>5</u>

Step-by-step explanation:

There is no ones place in decimals

41.<u>5</u>3

the tenth's place come first then the hundredth's and so on.

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1 year ago

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Random points for no reason what so ever

Stells [14]

Answer:

HEEYYYY

Step-by-step explanation:

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2 years ago

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how many ways are there to win the jackpot? how many ways are there to match 5 of 6 numbers? how many ways are there to match 4

musickatia [10]

The number of ways to match 5 of 6 numbers is 6 ways

The number of ways to match 4 of 6 numbers is 15 ways

The number of ways to match 3 of 6 numbers is 20 ways

To calculate number of ways to match 5 of 6 numbers we have to use to formula:

$nCr =\frac{n!}{(n - r)! . r !}$

$6C5=\frac{6!}{(6-5)! . 5!}$

$6C5=\frac{6!}{(1)! . 5!}$

$6C5=\frac{6.5.4.3.2.1}{1.5.4.3.2.1}$

$6C5=\frac{6}{1}$

$6C5= 6 \ ways$

∴ 6 ways are to match 5 of 6 numbers

To calculate number of ways to match 4 of 6 numbers we have to use to formula:

$nCr =\frac{n!}{(n - r)! . r !}$

$6C4=\frac{6!}{(6-4)! . 4!}$

$6C4=\frac{6!}{(2)! . 4!}$

$6C4=\frac{6.5.4.3.2.1}{2.1.4.3.2.1}$

$6C4=\frac{30}{2}$

$6C4= 15 \ ways$

∴ 15 ways are to match 4 of 6 numbers

To calculate number of ways to match 4 of 6 numbers we have to use to formula:

$nCr =\frac{n!}{(n - r)! . r !}$

$6C3=\frac{6!}{(6-3)! . 3!}$

$6C3=\frac{6!}{(3)! . 3!}$

$6C3=\frac{6.5.4.3.2.1}{3.2.1.3.2.1}$

$6C3=\frac{120}{6}$

$6C3= 20 \ ways$

∴ 20 ways are to match 3 of 6 numbers

Learn more about Jackpots here :

brainly.com/question/27116420

#SPJ4

6 0

1 year ago

I need some help, can't figure out this last question.

Damm [24]

He now has 36 percent

5 0

2 years ago