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TEA [102]
3 years ago
10

Multiply 640 times 3 using partial products

Mathematics
2 answers:
Leviafan [203]3 years ago
8 0
600×3plus40×3plus0×3=1920
Leno4ka [110]3 years ago
5 0
213r1 or 213.3repeating
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In a circle a chord 10 inches long is parallel to a tangent and bisects the radius drawn to the point of tangency. How long is t
Lorico [155]
Check the picture below.

keeping in mind that the point of tangency for a radius line and a tangent is alway a right-angle, since the "red" chord is parallel to the "green" tangent line outside, then the chord is cutting the "green" radius there in two equal halves at a right-angle, as you see in the picture.

we know the chord is 10 units long, so 5 + 5, since is perpendicularity with the radius will also cut the chord in two equal halves.

anyhow, all that said, we end up with triangle you see on the right-hand-side, and then we can just use the pythagorean theorem.

\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
-------\\
c=2a\\
a=a\\
b=5
\end{cases}\implies (2a)^2=a^2+5^2

\bf (2^2a^2)=a^2+25\implies 4a^2=a^2+25\implies 3a^2=25
\\\\\\
a^2=\cfrac{25}{3}\implies a=\sqrt{\cfrac{25}{3}}\implies a=\cfrac{\sqrt{25}}{\sqrt{3}}\implies a=\cfrac{5}{\sqrt{3}}
\\\\\\
\textit{and then we can \underline{rationalize the denominator} }
\\\\\\
a=\cfrac{5}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}}\implies a=\cfrac{5\sqrt{3}}{\sqrt{3^2}}\implies a=\cfrac{5\sqrt{3}}{3}

7 0
3 years ago
How can i get the volume??
Paladinen [302]
Length times width times height gives you the volume of things
6 0
3 years ago
Find the slope of the line passing through the given points.<br> (-3,7) (-1,4)
Amiraneli [1.4K]

Answer:

I think that5 it is the secend one

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Evaluate the following |10| |-7|
ahrayia [7]

|10| > |-7|

i hope that answers it

7 0
3 years ago
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A school district is considering moving the start of the school day at Groveland High from 8:00 a.m. to 9:00 a.m. to allow stude
DaniilM [7]

Answer:

The answer is "\bold{(7.1-8.3) \pm 1.665 \sqrt{\frac{(1.7)^2}{50}+\frac{(1.9)^2}{39}} }\\\\"

Step-by-step explanation:

Given values:

\bar{x_1}=7.1\\\\\bar{x_2}=8.3\\\\s_1=1.7\\\\s_2=1.9\\\\n_1=50\\\\n_2=39

Using formula:

\to (\bar{x_1} -\bar{x_2}) \pm t \sqrt{\frac{(s_1)^2}{n_1}+\frac{(s_1)^2}{n_2}} \\\\

Put the values in the above formula:

\to (7.1-8.3) \pm 1.665 \sqrt{\frac{(1.7)^2}{50}+\frac{(1.9)^2}{39}} \\\\

4 0
3 years ago
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