First set up your two equations:
x + y = 90
x = 2y - 30
Then substitute what x equals in the second equation into the first equation:
(2y -30) + y = 90
Now solve for y:
3y -30 = 90
3y = 120
y = 40
Then use y = 40 and substitute the value for y into one of your original equations and solve for x. I'll choose the first one, but either one will work.
x+ 40 = 90
x = 50
So your solution is x = 50 and y = 40
Answer:
Sin = -5/13
Cos = 12/13
Tan = -5/12
Step-by-step explanation:
Here you have 2 linear equations and are to solve this system. Both equations have already been solved for y, so you can set one of them = to the other one:
-2x+11 = -3x+21.
Then 3x-2x = 21 - 11, or x = 10 (answer)
Find y by subst. x = 10 into either of the given equations.
Solution is then (10, ? )
Answer:
I got 76 for #1 your welcome
Answer:
2.25 or 2 1/4
Step-by-step explanation:
Easy. you add them like regular numbers. 1/4 + 2 = 0.25 + 2 =2.25 and/or 2 1/4
