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Firdavs [7]
3 years ago
6

Explain how to find the x-intercept of the graph of y=-8x-12.

Mathematics
1 answer:
jeyben [28]3 years ago
8 0
The x-intercept is when y=0, so we plug that in our equation,
0=-8x-12. +12 on both sides to get 12=-8x. Divide by -8 to get x=-1.5
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Q(a+1) - 2q(a) if q(x) = x²+3x+4​
siniylev [52]

q(x) =  {x}^{2} + 3x + 4

_________________________________

Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

Let's do it...

q(a) =  {a}^{2} + 3a + 4

Multiply sides by -2 :

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Step (2)

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Let's do it...

q(a + 1) =  ({a + 1})^{2} + 3(a + 1) + 4 \\

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Step (3)

q(a + 1) - 2q(a) =

{a}^{2} + 5a + 8 - 2 {a}^{2} - 6a - 8 =  \\

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And we're done.

Thanks for watching buddy good luck.

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8 0
3 years ago
HELP WILL GIVE BRAINLIEST
tatiyna

Step-by-step explanation:

y = x - 4 and y = 4x + 2

=> x - 4 = 4x + 2

=> 3x = -6

=> x = -2

y = x - 4 = (-2) - 4 = -6

The solutions are x = -2 and y = -6.

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