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3 years ago

Explain how to find the x-intercept of the graph of y=-8x-12.

1 answer:

8 0

The x-intercept is when y=0, so we plug that in our equation,
$0=-8x-12$ . +12 on both sides to get $12=-8x$ . Divide by -8 to get $x=-1.5$

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siniylev [52]

$q(x) = {x}^{2} + 3x + 4$

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Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

Let's do it...

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Step (2)

To find q(a+1) we just need to put a+1 instead of x in q(x) function.

Let's do it...

$q(a + 1) = ({a + 1})^{2} + 3(a + 1) + 4 \\$

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Step (3)

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3 years ago

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Step-by-step explanation:

y = x - 4 and y = 4x + 2

=> x - 4 = 4x + 2

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