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mel-nik [20]
3 years ago
7

The legs of a right triangle are 3 units and 6 units. What is the length of the hypotenuse? Round your answer to the nearest hun

dredth.
5.20 units
6.71 units
9.00 units
18.00 units
Mathematics
2 answers:
garri49 [273]3 years ago
8 0
C =\sqrt{3 ^{2} + 6  ^{2} } = 6.7082

Round 6.7082
6.71

6.71 is your answer
kotykmax [81]3 years ago
6 0

Answer:

6.71

Step-by-step explanation:

I JUST TOOK THE TEST

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PLEASE HELP TIMED
Lerok [7]
Answer: C) (9x^4-x^3-x)/5
7 0
3 years ago
Which of the following are valid names for the given triangle? Check all that apply:
natka813 [3]

Answer:

A, C, E

Step-by-step explanation:

Only letters T, A, and X on the triangle can be used to describe it, regardless of the order they are in.

4 0
2 years ago
In the diagram below, DE and EF are tangent to O. Which equation could be solved to find X, the measure of DF.
Brut [27]

Answer:

The answer to your question is letter D

Step-by-step explanation:

Formula

                     m∠E = \frac{1}{2} ( DGF - DF)

Data

m∠E = 48°

DGF = 228°

DF = x°

Substitution

                    48° = \frac{1}{2} ( 228° - x°)

Solution

                                     2(48) = 228 - x°

                                     96 = 228 - x°

                                     96 - 228 = - x°

                                    - 132 = - x°

                                       x° = 132°

7 0
3 years ago
36 – 0.0048 = ? A. 35.9952 B. 35.1520 C. 35.0048 D. 36.0048
Tems11 [23]
If you would like to solve 36 - 0.0048, you can calculate this using the following step:

36 - 0.0048 = 35.9952

The correct result would be A. 35.9952.
6 0
3 years ago
Read 2 more answers
HELP What is the area of this figure?
Mademuasel [1]
The correct answer is:  [B]:  "40 yd² " .
_____________________________________________________
First, find the area of the triangle:

The formula of the area of a triangle, "A":

A = (1/2) * b * h ; 

in which:  " A = area (in units 'squared') ;  in our case, " yd² " ; 

                 " b = base length" = 6 yd.  

                 " h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
___________________________________________________
→  A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ; 
                                                                 
                                                                   =  " 24 yd² " .
___________________________________________________
Now, find the area, "A", of the square:

The formula for the area, "A" of a square:

   A = s² ;

in which:  "A = area (in "units squared") ; in our case, " yd² " ;
                 
                 "s = side length (since a 'square' has all FOUR (4) equal side lengths);

 A = s²  = (4 yd)² = 4² * yd² =  "16 yd² "
_________________________________________________
Now, we add the areas of BOTH the triangle AND the square:
_________________________________________________
        →  " 24 yd²  +  16 yd² " ; 

to get:  " 40 yd² " ;  which is:  Answer choice:  [B]:  " 40 yd² " .
_________________________________________________
4 0
3 years ago
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