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3 years ago

7

The legs of a right triangle are 3 units and 6 units. What is the length of the hypotenuse? Round your answer to the nearest hun

dredth.
5.20 units
6.71 units
9.00 units
18.00 units

2 answers:

garri49 [273]3 years ago

8 0

C = $\sqrt{3 ^{2} + 6 ^{2} }$ = 6.7082

Round 6.7082
6.71

6.71 is your answer

kotykmax [81]3 years ago

6 0

Answer:

6.71

Step-by-step explanation:

I JUST TOOK THE TEST

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7. Given f(x) = 6(1 - x) +11, what is the value of f(8) ?

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Answer:

f(8)=-31

Step-by-step explanation:

since 8 replaces x in f(x), x should be substituted as 8 in the expression. From there, after you substitute, it becomes 6(1-8)+11. Simplifying that expression is now 6(-7)+11. Multiply 6 and -7, you get -42. -42+11=-31. I hope this helps :)

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3 years ago

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3 years ago

Read 2 more answers

Complete the table of values

Agata [3.3K]

Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify!

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, $3^{-2} =
\frac{1}{3^{2} }$ .
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, $(\frac{3}{4}) ^{3} = \frac{ 3^{3} }{4^{3} }$ .
3) The zero exponent rule<span> says that any number raised to zero is 1. For example, $3^{0} = 1$ .
</span>

Back to the Problem:
Problem 1
The x-values are in the left column. The title of the right column tells you that the function is $y = 4^{-x}$ . The x-values are:
<span>1) x = 0
</span>Plug this into $y = 4^{-x}$ to find letter a:
$y = 4^{-x}\\
y = 4^{-0}\\
y = 4^{0}\\
y = 1$
<span>
2) x = 2
</span>Plug this into $y = 4^{-x}$ to find letter b:
$y = 4^{-x}\\ 
y = 4^{-2}\\ 
y = \frac{1}{4^{2}} \\ 
y= \frac{1}{16}$
<span>
3) x = 4
</span>Plug this into $y = 4^{-x}$ to find letter c:
$y = 4^{-x}\\ 
y = 4^{-4}\\ 
y = \frac{1}{4^{4}} \\ 
y= \frac{1}{256}$
<span>

Problem 2
</span>The x-values are in the left column. The title of the right column tells you that the function is $y = (\frac{2}{3})^x$ . The x-values are:
<span>1) x = 0
</span>Plug this into $y = (\frac{2}{3})^x$ to find letter d:
$y = (\frac{2}{3})^x\\
y = (\frac{2}{3})^0\\
y = 1$
<span>
2) x = 2
</span>Plug this into $y = (\frac{2}{3})^x$ to find letter e:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\
y = \frac{4}{9}$
<span>
3) x = 4
</span>Plug this into $y = (\frac{2}{3})^x$ to find letter f:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}$
<span>
-------

Answers:
a = 1
b = </span> $\frac{1}{16}$ <span>
c = </span> $\frac{1}{256}$
d = 1
e = $\frac{4}{9}$
f = $\frac{16}{81}$

5 0

3 years ago

Round 18.194 to the place named tenth hundred ones

Novay_Z [31]

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hundredth place: 18.19

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tens place: 20

hundred place: 0

I didn't know which one you needed so I did a bunch

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3 years ago

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Tasya [4]

Answer:

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Step-by-step explanation:

I. Given t = teacher, s = student

When 1 teacher per 22 students so...

s = 22t

If there're 10 teachers

s = 22(10)

= 220 or $\frac{t}{s} = \frac{1}{22}$

Hope that help :)

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3 years ago