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Colt1911 [192]
3 years ago
15

Draw a graph that shows the equation V = 4 + 2t, where V is the total volume of water in a bucket and t is the elapsed time in m

inutes?

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
7 0
Since v=4+2t its linear equation in the graph is a straight line. Put t=0,1,2.....give value of v and draw it. For example, if t=-2, v= 0 so the point on XOY axes is A(-2, 0). I hope that this is the answer that you were looking for and it has helped you.
Rufina [12.5K]3 years ago
3 0

Answer:  The graph is attached.

Step-by-step explanation:  We are given to draw the graph of the following equation:

V=4+2t~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i),

where 'V' is the total volume of water in a bucket and 't' is the elapsed time in minutes.

Since equation (i) is a linear equation in two unknown variables, so the graph will be a straight line.

To draw the graph of a straight line, we need at least two points to be plotted on the graph paper and then joined straight.

If t = 0, then from equation (i), we have

V=4+2\times 0=4.

If t = -2, then from equation (i), we have

V=4+2\times (-2)=0.

So, (t. V) = (0, 4) and (-2, 0) are two points on the graph, if 't' is plotted along X-axis and 'V' is plotted along Y-axis.

These two points are joined to draw the graph of the given equation. Please see the attached graph below.

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The amount needed such that when it comes time for retirement is $396721.78.

Step-by-step explanation:

Given : An individual can make monthly withdraws in the amount of $2,154 for 30 years from an account paying 5.1% compounded monthly.

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Solution :

Using the formula of monthly payment,

Monthly payment, M=\frac{\text{Amount}}{\text{Discount factor}}

Discount factor D=\frac{1-(1+i)^{-n}}{i}  

Where,

Amount = ?

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Rate r= 5.1%=0.051

i=\frac{0.05}{12}=0.00425

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Substitute all the values,

D=\frac{1-(1+i)^{-n}}{i}

D=\frac{1-(1+0.00425)^{-360}}{0.00425}

D=\frac{1-(1.00425)^{-360}}{0.00425}

D=\frac{1-0.21723}{0.00425}  

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<h3>How to determine the equivalent expression?</h3>

The expression is given as:

\frac{14x^4y^6}{7x^8y^2}

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\frac{14x^4y^6}{7x^8y^2} = \frac{2x^4y^6}{x^8y^2}

Apply the law of indices

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Hence, the equivalent expression of \frac{14x^4y^6}{7x^8y^2} is \frac{2y^{4}}{x^{4}}

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