Answer: The graph is attached.
Step-by-step explanation: We are given to draw the graph of the following equation:
![V=4+2t~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i),](https://tex.z-dn.net/?f=V%3D4%2B2t~~~~~~~~~~~~~~~~~~~~~~~~~~~~~%28i%29%2C)
where 'V' is the total volume of water in a bucket and 't' is the elapsed time in minutes.
Since equation (i) is a linear equation in two unknown variables, so the graph will be a straight line.
To draw the graph of a straight line, we need at least two points to be plotted on the graph paper and then joined straight.
If t = 0, then from equation (i), we have
![V=4+2\times 0=4.](https://tex.z-dn.net/?f=V%3D4%2B2%5Ctimes%200%3D4.)
If t = -2, then from equation (i), we have
![V=4+2\times (-2)=0.](https://tex.z-dn.net/?f=V%3D4%2B2%5Ctimes%20%28-2%29%3D0.)
So, (t. V) = (0, 4) and (-2, 0) are two points on the graph, if 't' is plotted along X-axis and 'V' is plotted along Y-axis.
These two points are joined to draw the graph of the given equation. Please see the attached graph below.