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Bezzdna [24]
1 year ago
12

Find the coordinates of the vertices of each figure after a reflection over the given axis.

Mathematics
1 answer:
pochemuha1 year ago
4 0

The coordinates of the vertices after the reflection over the x-axis are A' (2, -3) B' (4, 5) and C' (-1, -2)

Given,

A triangle ABC with vertices A(2,3) , B(4,-5), and C(-1,2)

To find the coordinates of the vertices of each figure after a reflection over the given axis.

Now, According to the question:

We should know that:

You should know that you can predict changes in coordinates after translations without a graph or anything like that.

(x, y) reflected over the x axis = (x, -y)

(x, y) reflected over the y axis = (-x, y)

(x, y) rotated 90 degrees around the origin = (y, -x)

(x, y) rotated 180 degrees around the origin = (-x, -y)

(x, y) rotated 270 degrees around the origin = (-x, y)

So here's our set of points.

A(2,3) , B(4,-5), and C(-1,2)

Here's those points reflected over the x axis.

A' (2, -3) B' (4, 5) and C' (-1, -2)

Hence, The coordinates of the vertices after the reflection over the x-axis are A' (2, -3) B' (4, 5) and C' (-1, -2)

Learn more about Reflection x - axis at:

brainly.com/question/15175017

#SPJ1

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If someone could help me answer this and possibly give me a step-by-step for future reference that'd be great thanks.
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Answer:

Let's look at the Venn diagram and the data we have:

There are 12 pupils

9 have a brother

7 have a sister

2 have neither.

Now let's look at the diagram.

We know that the circle B represents the pupils who have a brother

Circle S represents the students that have a sister.

Then the intersection of the circles, represents the number of students that have both.

And the space outside the circles represents the pupils that do not have a brother nor a sister.

Then the first thing we can complete is a 2 in the bottom left corner, because we already know that there are 2 pupils that do not have brothers nor sisters.

Now let's find the number of students that have both, brothers and sisters:

There are 12 pupils.

9 have a brother

7 have a sister

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if we add that, we get:

9 + 7 + 2 = 18

This is larger than 12, this means that we are counting some of the students more than once.

If X is the number of students that we are counting twice, we should have:

18 - X  = 12

18 -12 = X = 6

There are 6 students who we are counting twice, and this happens because these 6 students have a brother and a sister.

Then in the intersection of both circles we should put a 6.

At the left of that (in the part that we have only circle B) we need to write the number of students that only have a brother, this is the number of students that have a brother minus the number of pupils that have a brother and a sister, this is:

9 - 6 = 3

We need to write a 3 in that square.

And in the last square (the one that is only one circle S) we need to write the number of pupils that only have a sister, this is calculated in the same way than before, this is:

7 - 6 = 1

We need to write a 1 in the rightmost square.  

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