I answered a similar problem yesterday.
In three coin tosses there are 8 possible outcomes:
H H H
H H T
H T H
T H H
T T H
T H T
H T T
T T T
Of those results, four out of the eight have at least 2 tails and so the probability is (4/8) or50%
If you need the probability of getting EXACTLY 2 tails then the probability is (3/8) or .375
Answer:
The given power series 
is a solution of the differential equation (1+x^2)y' + 2xy = 0
Step-by-step explanation:
This is a very trivial exercise, follow the steps below for the solution:
Step 1: Since n = 0, 1, 2, 3, 4, ........, Substitute the values of n into equation (1) below.
.....................(1)
Step 2: Find the derivative of y, i.e. y'
Step 3: Substitute y and y' into equation (2) below:
(Verified)
Since the LHS = RHS = 0, the given power series is a solution of the differential equation (1+x^2)y' + 2xy = 0
Answer:
I think it is D. Because x=x and there's infinite possibilities.
When you divide 1/12 with long division, you get 0.08333...
The 3s keep going forever, and they never end.
