20% of what number is 98?
2 answers:
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Answer:
D. x = 0; y = -6
Step-by-step explanation:
There is a vertical asymptote at the value of x that makes the denominator zero. That value is x=0. This is sufficient to choose the correct answer.
When x gets large, the term 1/x nears zero, so the value of y nears -6. This is the horizontal asymptote.
vertical asymptote: x = 0; horizontal asymptote: y = -6
<span>1.
P(</span>at least one of the calculators is defective)=
1- P(none of the selected calculators is defective).
2.
P(none of the selected calculators is defective)
=n(ways of selecting 4 non-defective calculators)/n(total selections of 4)
3.
selecting 4 non-defective calculators can be done in C(35, 4) many ways,
where
while, the total number selections of 4 out of 18+35=53 calculators can be done in C(53, 4) many ways,
4. so, P(none of the selected calculators is defective)=
5. P(at least one of the calculators is defective)=
1- P(none of the selected calculators is defective)=1-0.18=0.82
Answer:0.82
P(</span>at least one of the calculators is defective)=
1- P(none of the selected calculators is defective).
2.
P(none of the selected calculators is defective)
=n(ways of selecting 4 non-defective calculators)/n(total selections of 4)
3.
selecting 4 non-defective calculators can be done in C(35, 4) many ways,
where
while, the total number selections of 4 out of 18+35=53 calculators can be done in C(53, 4) many ways,
4. so, P(none of the selected calculators is defective)=
5. P(at least one of the calculators is defective)=
1- P(none of the selected calculators is defective)=1-0.18=0.82
Answer:0.82