Answer:
$8/mile
Step-by-step explanation:
Total distance walked was 2 1/4 mi + 5 1/2 mi = 7 3/4 mi. Please note: you must use the " / " symbol to indicate division; "2 1 4" is unclear.
$62
Unit rate = $ per mile = --------------- = $8/mile
7 3/4 mi
Answer:
(-∞, -1-(2/3)√2] ∪ [-1+(2/3)√2, ∞)
Step-by-step explanation:
To make it easier to differentiate, we'll rewrite the function as ...
h(x) = 2/(x-5) -1/(x-2)
Then the derivative is ...
h'(x) = -2/(x-5)^2 +1/(x-2)^2
This will be zero when ...
-2(x-2)^2 +(x-5)^2 = 0
-2(x^2 -4x +4) +(x^2 -10x +25) = 0
-x^2 -2x +17 = 0
x^2 +2x +1 = 17 +1
x +1 = ±√18 = ±3√2
x = -1 ±3√2
The values of the function at these locations are ...
h(-1-3√2) = -1 +(2/3)√2 ≈ -1.9428
h(-1+3√2) = -1 -(2/3)√2 ≈ -0.0572
Then the range of h(x) is ...
(-∞, -1-(2/3)√2] ∪ [-1+(2/3)√2, ∞)
Answer:
64
Step-by-step explanation:
As the angle in the bottom is shared and the 2 sides are proportional, one is 40 and 80 (times 2) and the other, 25 and 50 (times 2) so the triangles are similar so all we do is multiply 32 by 2 as its the rule. So the answer is 64.
Answer:
A.]A chord of a circle of diameter 40 cm subtends an angle of 70° at the centre of the circle.
Solution given;
diameter [d]=40cm
centre angle [C]=70°
(a) Find the perpendicular distance be tween the chord and the centre of the circle.
Answer:
we have
the perpendicular distance be tween the chord and the centre of the circle=[P]let
we have
P=d Sin (C/2)
=40*sin (70/2)
=22.9cm
<u>the</u><u> </u><u>perpendicular distance be tween the chord and the centre of the </u><u>circle</u><u> </u><u>is</u><u> </u><u>2</u><u>2</u><u>.</u><u>9</u><u>c</u><u>m</u><u>.</u>
(b) Using = 3.142, find the length of the minor arc.
Solution given;
minor arc=
=<u>2</u><u>4</u><u>.</u><u>4</u><u>4</u><u>c</u><u>m</u>
<u>the length of the minor arc.</u><u> </u><u>is</u><u> </u><u>2</u><u>4</u><u>.</u><u>4</u><u>4</u><u>cm</u><u>.</u>
B.]In the diagram, XZ is a diameter of the cir cle XYZW, with centre O and radius 15/2 cm.
If XY = 12 cm, find the area of triangle XYZ.
Solution given:
XY=12cm
XO=15/2cm
XZ=2*15/2=15cm
Now
In right angled triangle XOY [inscribed angle on a diameter is 90°]
By using Pythagoras law
h²=p²+b²
XZ²=XY²+YZ²
15²=12²+YZ²
YZ²=15²-12²
YZ=
:.
base=9cm
perpendicular=12cm
Now
Area of triangle XYZ=½*perpendicular*base
=½*12*9=54cm²
the area of triangle XYZ is <u>5</u><u>4</u><u>c</u><u>m</u><u>²</u><u>.</u>