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Elena-2011 [213]
4 years ago
14

The formula for the circumference of a circle is C = 2LaTeX: \pi π r. If the circumference of the circle is approximately 32.7 i

nches, find the radius.
Mathematics
1 answer:
Alexeev081 [22]4 years ago
8 0

Answer:

r=5.2\ in

Step-by-step explanation:

we know that

The circumference of a circle is equal to

C=2\pi r

we have

C=32.7\ in

assume

\pi =3.14

substitute the values and solve for r

32.7=2(3.14) r

r=32.7/[2(3.14)]

r=5.2\ in

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Find the product of 1.05 and 0.7 <br><br> A 73.5<br> B 7.35<br> C 0.735<br> D 0.0735
ANEK [815]
1.05 x 0.7 = 

0.735

C 0.735
6 0
4 years ago
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Karl participated in a two-day charity walk. His parents donated money for each mile he walked. Karl walked 2 1 4 miles on the f
eduard

Answer:

$8/mile

Step-by-step explanation:

Total distance walked was 2  1/4 mi  +  5  1/2 mi = 7  3/4 mi.  Please note: you must use the " / " symbol to indicate division;  "2 1 4" is unclear.

                                           $62

Unit rate = $ per mile = --------------- = $8/mile

                                        7  3/4 mi

7 0
3 years ago
What is the range of the function: h(x)=x+1/x^2 - 7x+10
Elina [12.6K]

Answer:

  (-∞, -1-(2/3)√2] ∪ [-1+(2/3)√2, ∞)

Step-by-step explanation:

To make it easier to differentiate, we'll rewrite the function as ...

  h(x) = 2/(x-5) -1/(x-2)

Then the derivative is ...

  h'(x) = -2/(x-5)^2 +1/(x-2)^2

This will be zero when ...

  -2(x-2)^2 +(x-5)^2 = 0

  -2(x^2 -4x +4) +(x^2 -10x +25) = 0

  -x^2 -2x +17 = 0

  x^2 +2x +1 = 17 +1

  x +1 = ±√18 = ±3√2

  x = -1 ±3√2

The values of the function at these locations are ...

  h(-1-3√2) = -1 +(2/3)√2 ≈ -1.9428

  h(-1+3√2) = -1 -(2/3)√2 ≈ -0.0572

Then the range of h(x) is ...

  (-∞, -1-(2/3)√2] ∪ [-1+(2/3)√2, ∞)

5 0
3 years ago
1. Find the value of x. The diagram is not to scale.​
nika2105 [10]

Answer:

64

Step-by-step explanation:

As the angle in the bottom is shared and the 2 sides are proportional, one is 40 and 80 (times 2) and the other, 25 and 50 (times 2) so the triangles are similar so all we do is multiply 32 by 2 as its the rule. So the answer is 64.

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3 years ago
Show Workings.<br>Question is in attached image.​
Mashutka [201]

Answer:

A.]A chord of a circle of diameter 40 cm subtends an angle of 70° at the centre of the circle.

Solution given;

diameter [d]=40cm

centre angle [C]=70°

(a) Find the perpendicular distance be tween the chord and the centre of the circle.

Answer:

we have

the perpendicular distance be tween the chord and the centre of the circle=[P]let

we have

P=d Sin (C/2)

=40*sin (70/2)

=22.9cm

<u>the</u><u> </u><u>perpendicular distance be tween the chord and the centre of the </u><u>circle</u><u> </u><u>is</u><u> </u><u>2</u><u>2</u><u>.</u><u>9</u><u>c</u><u>m</u><u>.</u>

(b) Using = 3.142, find the length of the minor arc.

Solution given;

minor arc=\frac{70}{360}*πd=\frac{7}{36}*3.142*40

=<u>2</u><u>4</u><u>.</u><u>4</u><u>4</u><u>c</u><u>m</u>

<u>the length of the minor arc.</u><u> </u><u>is</u><u> </u><u>2</u><u>4</u><u>.</u><u>4</u><u>4</u><u>cm</u><u>.</u>

B.]In the diagram, XZ is a diameter of the cir cle XYZW, with centre O and radius 15/2 cm.

If XY = 12 cm, find the area of triangle XYZ.

Solution given:

XY=12cm

XO=15/2cm

XZ=2*15/2=15cm

Now

In right angled triangle XOY [inscribed angle on a diameter is 90°]

By using Pythagoras law

h²=p²+b²

XZ²=XY²+YZ²

15²=12²+YZ²

YZ²=15²-12²

YZ=\sqrt{81}=9cm

:.

base=9cm

perpendicular=12cm

Now

Area of triangle XYZ=½*perpendicular*base

=½*12*9=54cm²

the area of triangle XYZ is <u>5</u><u>4</u><u>c</u><u>m</u><u>²</u><u>.</u>

3 0
3 years ago
Read 2 more answers
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