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scoundrel [369]
3 years ago
13

What is the solution set of the following equation?

Mathematics
1 answer:
Anna [14]3 years ago
8 0
Im getting no solution in my calculator... Maybe 0? Thats a solution though so I'm not sure
You might be interested in
Help me with this please.
andriy [413]
1. bc/3 + a/xy + 3/ab
= b^2cxya + 3a^2b + 9xy/3xyab

2. (5/3y) + 2y - 12
=11/3y - 2

3. ?

Hope this helps and right! :)) Good luck
4 0
2 years ago
SOMEONE PLEASE HELP ME ASAP THIS IS ALMOST DUE ILL MARK BRAINLIEST!!!!
makkiz [27]

Answer:

153

Step-by-step explanation:

If the table adds up to 20 and opened toe counts for 45% of the total. then 45% of 340 is 153 !

3 0
2 years ago
What is the product of 6(x^2-1) * 6x-1/6(x+1)
umka2103 [35]
(6(x^2-1))*((6x-1)/(6(x+1))
(6((x+1)(x-1)))((6x-1)/(6(x+1))
(6(x-1))*(6x-1)/(6)
(x-1)(6x-1)
6x^2-x-6x+1
6x^2-7x+1
6 0
3 years ago
What values complete each statement?
aliya0001 [1]

For this case we have:

By properties of the radicals \sqrt {a} = a ^{\frac {1} {2}}

So:

(\sqrt {7}) ^ 2 = (7 ^ {\frac {1} {2}}) ^ 2.

Now, for power properties we have:

(b ^ {\frac {c} {d}}) ^ e = b ^ {\frac {c * e} {d}}

Thus, (7 ^ {\frac {1} {2}}) ^ 2 = 7 ^ {\frac {2} {2}} = 7

So:

7 ^ {\frac {1} {2}} = \sqrt {7}in its radical form

Answer:

(\sqrt {7}) ^ 2 = (7 ^ {\frac {1} {2}}) ^ 2= 7 ^ {\frac {2} {2}} = 7 in its simplest form.

7 ^ {\frac {1} {2}} = \sqrt {7}in its radical form


4 0
3 years ago
If the needle below is spun twice and the letters are recorded both times , which of the following would be the probability it w
ANTONII [103]
2/3 is the correct answer
4 0
2 years ago
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