Not sure what the mess above me says, but basically as long as you have an equation for the circle, you can plug the coordinates of your point into the x and y values of the equation and see if it equals out. If you don’t have an equation, you can just make one. Use (f-k)^2+(x-h)^2=r^2 where h and k are the coordinates of the center of the circle and r is the radius. Hope this helps!
Here are the answers for the Unit 7 lesson 1 Geometry Practice!
1. C - If a line is tangent to a circle then...
2. D - 120 Degrees
3. B - 47 Degrees
4. C - 4.8 Units
5. A, B, D - A tangent line is perpendicular to the radius..., A tangent line is perpendicular to the diameter..., A tangent line intersects...
6. B - y = 2/3x + 1/3
7. A - 6.5
8. B, D - 8 & 4 square-root(21), 10 & 10 square-root(3)
9. A, C, D - 8 & 4 square-root(3), 3 & 5, 2 & 2 square-root(5)
10. D - 78 cm
Just took it these are 100%
Answer:
k = -23
Step-by-step explanation:
-14=k+9
Subtract 9 from each side
-14-9 = k+9-9
-23 = k
Answer:
y = -1/3x + 8
Step-by-step explanation:
If two lines are perpendicular, the signs of the slope must be opposite and the slopes are reciprocals.
(basically if one is say -2/3, the other is 3/2. just flip it upside down)
So this slope is 3, so the new slope should be -1/3
The equation is now y = -1/3x + b
To find b, substitute (-9,5) in the equation
y = -1/3x + b
5 = -1/3(9) + b
5 = -3 + b
8 = b
So the equation is y = -1/3x + b
