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pantera1 [17]
3 years ago
6

What is 999.765 rounding to the neareast hundred thousand

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
7 0

Answer:

1,000

Step-by-step explanation:

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g A sample of 3 items is chosen at random from a box containing 20 items, out of which 4 are defective. Let X be the number of d
professor190 [17]

Answer:

The variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

The variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

Step-by-step explanation:

The variable <em>X</em> is defined as, <em>X</em> = number of defective items in the sample.

In a sample of 20 items there are 4 defective items.

The probability of selecting a defective item is:

P (X)=\frac{4}{20}=0.20

A random sample of <em>n</em> = 3 items are selected at random.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 3 and <em>p </em>= 0.20.

The variance of a Binomial distribution is:

V(X)=np(1-p)

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)=3\times0.20\times(1-0.20)=0.48

Compute the standard deviation (σ (X)) as follows:

\sigma (X)=\sqrt{V(X)}=\sqrt{0.48}=0.693

Thus, the variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

Now compute the variance of (20 - X) as follows:

V(20-X)=V(20)+V(X)-2Cov(20,X)=0+0.48-0=0.48

Compute the standard deviation of (20 - X) as follows:

\sigma (20-X)=\sqrt{V(20-X)} =\sqrt{0.48}0.693

Thus, the variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

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2 years ago
Which expression is equivalent to 454•41/4 /1/2 4. 1/2
givi [52]

Answer:

2

Step-by-step explanation:

if you work inside parentheses first you get:

4^3/2 ÷ 4^1/2 which is 4

4^1/2 = \sqrt{4} which is 2

8 0
3 years ago
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