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Ne4ueva [31]
3 years ago
14

The function below takes two arguments: a dictionary of strings (keys) to integers (values) a_dict and a list of strings key_lis

t. All of the strings in the list are keys to the dictionary. Complete the function such that it looks up each of the keys in the list and returns a list of their associated values. The order of the values in the list is based on the order of the keys in key_list. For example, with the dictionary {"puffin": 5, "corgi": 2, "three": 3} and the list ["three", "corgi"], your function should return [3, 2]. student.py
Computers and Technology
1 answer:
vitfil [10]3 years ago
8 0

Answer:

  1. def getData(a_dict, key_list):
  2.    result = []
  3.    for key in key_list:
  4.        result.append(a_dict[key])
  5.    
  6.    return result  
  7. result = getData( {"puffin": 5, "corgi": 2, "three": 3} , ["three", "corgi"])
  8. print(result)

Explanation:

Let's define a function <em>getData() </em>with two parameters,<em> a_dict </em>and <em>key_list</em> as required by the question (Line 1).

Since the function is to return a list of associated values of dictionaries, a new list,<em> result</em>,  is declared and initialized with empty values (Line 2).

Next, use for-loop to traverse through every string in the input <em>key_list </em>(Line 4) and use the traversed key to address the value in the<em> a_dict </em>and add it to the <em>result</em> list (Line 5)

At last, return the <em>result </em>list as output (Line 7)

We can test the function using the test case from the question and we shall see the output as follows:

[3, 2]

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Write a program that prompts the user to enter in a postive number. Only accept positive numbers - if the user supplies a negati
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Answer:

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#include <iostream>

using namespace std;

int main() {

   int num, prime=0;

   do

   {

       cout<<"Enter a positive number."<<endl;

       cin>>num;

       if(num<1)

       {

           cout<<"Invalid number. Enter a positive number"<<endl;

           cin>>num;

       }

   }while(num<1);

   

   if(num==1 || num==2 || num==3)

       cout<<num<<" is a prime number."<<endl;

   else if(num%2 == 0)

       cout<<num<<" is not a prime number."<<endl;

   else

   {

       for(int k=3; k<num/2; k++)

       {

           if(num%k == 0)

               prime++;

       }    

   if(prime>1)

       cout<<num<<" is not a prime number."<<endl;

   else

       cout<<num<<" is a prime number."<<endl;

   }

}

OUTPUT

Enter a positive number.

-7

Invalid number. Enter a positive number

0

Enter a positive number.

79

79 is a prime number.

Explanation:

The user input is validated for positivity. A do while loop along with an if statement is implemented for verification.

do

   {

       cout<<"Enter a positive number."<<endl;

       cin>>num;

       if(num<1)

       {

           cout<<"Invalid number. Enter a positive number"<<endl;

           cin>>num;

       }

   }while(num<1);

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