The given problem describes a binomial distribution with p = 60% = 0.6. Given that there are 400 trials, i.e. n = 400.
a.) The mean is given by:

The standard deviation is given by:

b.) The mean means that in an experiment of 400 adult smokers, we expect on the average to get about 240 smokers who started smoking before turning 18 years.
c.) It would be unusual to observe <span>340 smokers who started smoking before turning 18 years old in a random sample of 400 adult smokers because 340 is far greater than the mean of the distribution.
340 is greater than 3 standard deviations from the mean of the distribution.</span>
Answer:
Does Not Factor
Step-by-step explanation:
No way to factor this.
<span>to find the solution to this problem, we must understand that the sum of the amount that the customer could be bought is $12. $4.75 pound of kumquats and Asian pears for $3.75 mean mathematically as $12. $4.75 kumquats + $3.75 Asian, this last sum is equal to $12, so the true answer is the choice B: 4.75k + 3.75p = 12 Hope this helps. Let me know if you need additional help!</span>
<h3>
Answer: -3x-3y=-30= x=−y+10 </h3><h3>x+y+10= x=−y+10</h3>
Only Table 2 shows direct variation. Every y value is 7 times the associated x value.