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2 years ago

Factor Completely: x²+x+8

Mathematics

1 answer:

Igoryamba2 years ago

7 0

Answer:

Does Not Factor

Step-by-step explanation:

No way to factor this.

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Anyone know this i need help this is for a final

Nuetrik [128]

For every week that goes on, the tiger’s weight increases by 4 lbs.

(1+4=5, 5+4=9, 9+4=13, 13+4=17)

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2 years ago

What is the area of this face

jeka57 [31]

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3 years ago

Read 2 more answers

What is the monthly payment rate for a $20,000 loan for 4 years with an annual interest rate of 4.8%

yarga [219]

Answer:

96048

Step-by-step explanation:

times 20000 by 4.8 then times 4 by 12 and add your answers

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2 years ago

How would you best describe the two students outside the circles?

ruslelena [56]

Answer:

A. They are boys who are not in sixth grade and don't wear glasses.

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2 years ago

In 2018, the population will grow over 700,000.The population of a city in 2010 was 450,000 and was growing at a rate of 5% per

Firlakuza [10]

Answer:

The year is 2020.

Step-by-step explanation:

Let the number of years passed since 2010 to reach population more than 7000000 be 'x'.

Given:

Initial population is, $P_0=450,000$

Growth rate is, $r=5\%=0.05$

Final population is, $P=700,000$

A population growth is an exponential growth and is modeled by the following function:

$P=P_0(1+r)^x$

Taking log on both sides, we get:

$\log(P)=\log(P_0(1+r)^x)\\\log P=\log P_0+x\log (1+r)\\x\log (1+r)=\log P-\log P_0\\x\log(1+r)=\log(\frac{P}{P_0})\\x=\frac{\log(\frac{P}{P_0})}{\log(1+r)}$

Plug in all the given values and solve for 'x'.

$x=\frac{\log(\frac{700,000}{450,000})}{\log(1+0.05)}\\x=\frac{0.192}{0.021}=9.13\approx 10$

So, for $x > 9.13$ , the population is over 700,000. Therefore, from the tenth year after 2010, the population will be over 700,000.

Therefore, the tenth year after 2010 is 2020.

8 0

2 years ago