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Svetlanka [38]
4 years ago
10

How would I rearrange this equation to make

da t" alt="- \lambda t" align="absmiddle" class="latex-formula"> the subject?
e^{-\lambda t} = \frac{N}{M}
Mathematics
1 answer:
Vinil7 [7]4 years ago
6 0
Easy
remember
ln(e^x)=x
so

e^{-thingt}= \frac{N}{M}
take the ln of booth sides
-λt=ln \frac{N}{M}
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you have $18 to buy a pepper.Pepper cost $1.50 each.Write and solve an inequality that represents the number of peppers you can
MatroZZZ [7]
18 is less than or equal to x+1.50. You  can buy 11 Peppers for $1.50 each.
7 0
4 years ago
The sum of Bernice’s age and her<br> mother’s age is 63. Bernice is 21. What is her mother’s age?
harina [27]

Answer:

her age would be 42

Step-by-step explanation:

63-42=21

8 0
3 years ago
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What kind of triangles are these?
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5)isosceles triangle 6)scalene triangle 7)equilateral triangle

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5 0
3 years ago
A particle moves along the curve below. y = √ 8 + x 3 As it reaches the point ( 1 , 3 ) , the y -coordinate is increasing at a r
Dmitry [639]

Answer:

<em>The x-coordinate is changing at 10 cm/s</em>

Step-by-step explanation:

<u>Rate of Change</u>

Suppose two variables x and y are related by a given function y=f(x). If they both change with respect to a third variable (time, for instance), the rate of change of them is computed as the derivative using the chain rule:

\displaystyle \frac{dy}{dt}=\frac{dy}{dx}\cdot \frac{dx}{dt}

We have

y=\sqrt{8+x^3}

Or, equivalently

y^2=8+x^3

We need to know the rate of change of x respect to t. We'll use implicit differentiation:

\displaystyle 2y\cdot \frac{dy}{dt}=3x^2\cdot \frac{dx}{dt}

Solving for dx/dt

\displaystyle \frac{dx}{dt}=\frac{2y\cdot \frac{dy}{dt}}{3x^2}

Plugging in the values x=1, y=3, dy/dt=5

\displaystyle \frac{dx}{dt}=\frac{2(3)\cdot 5}{3\cdot 1^2}=10

The x-coordinate is changing at 10 cm/s

7 0
3 years ago
6 libras de café y 5 de azúcar costaron 227 pesos y 5 libras de café y 4 libras de azúcar (a los mismos precios) costaron 188 pe
nlexa [21]

Answer:

The price of one pound of coffee is 32 pesos

The price of one pound of sugar is 7 pesos

Step-by-step explanation:

The question in English is

6 pounds of coffee and 5 pounds of sugar cost 227 pesos and 5 pounds of coffee and 4 pounds of sugar (at the same prices) cost 188 pesos Find the price of one pound of coffee and one pound of sugar.

Let

x-----> the price of one pound of coffee

y-----> the price of one pound of sugar

we know that

6x+5y=227 -----> equation A

5x+4y=188 ----> equation B

Solve the system of equations by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution is the point (32,7)

see the attached figure

therefore

The price of one pound of coffee is 32 pesos

The price of one pound of sugar is 7 pesos

6 0
4 years ago
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