Answer:
1/6
Step-by-step explanation:
because there is only one number 3 there is a 1/6 chance of you getting a 3
.777777777777777
or
388888889/500000000
Answer:
Step-by-step explanation:
y = 2x - 3 --------------(i)
y = x² - 2x - 8 -----------(ii)
Substitute y = x² - 2x - 8 in equation (i)
x² - 2x - 8 = 2x - 3
x² - 2x - 8 - 2x + 3 = 0
x² - 2x -2x - 8 + 3 = 0
x² - 4x - 5 = 0
x² + 1x - 5x -5 = 0
x(x + 1) - 5(x + 1) = 0
(x + 1)(x - 5) = 0
x + 1 =0 ; x -5 = 0
x = -1 ; x = 5
When x = -1; y =2*(-1) - 3 = -2 -3 = -5
When x = 5; y = 2*5 - 3 = 10-3 = 7
Answer:
if your looking for the next in line it would be 56 but i dont really understand the question
Step-by-step explanation:
Given:
A bag contains 2 red pens, 4 blue pens, 3 black pens, and 1 green pen.
Once a pen is selected, it is replaced, and then another pen is selected.
To find:
The probability of getting blue pens in both draws, i.e., P(blue and blue).
Solution:
We have,
Number of red pens = 2
Number of blue pens = 4
Number of black pens = 3
Number of green pen = 1
Total number of pens = ![2+4+3+1](https://tex.z-dn.net/?f=2%2B4%2B3%2B1)
= ![10](https://tex.z-dn.net/?f=10)
The probability of getting a blue pen is:
![P(\text{Blue})=\dfrac{\text{Number of blue pens}}{\text{Total number of pens}}](https://tex.z-dn.net/?f=P%28%5Ctext%7BBlue%7D%29%3D%5Cdfrac%7B%5Ctext%7BNumber%20of%20blue%20pens%7D%7D%7B%5Ctext%7BTotal%20number%20of%20pens%7D%7D)
![P(\text{Blue})=\dfrac{4}{10}](https://tex.z-dn.net/?f=P%28%5Ctext%7BBlue%7D%29%3D%5Cdfrac%7B4%7D%7B10%7D)
![P(\text{Blue})=0.4](https://tex.z-dn.net/?f=P%28%5Ctext%7BBlue%7D%29%3D0.4)
Once a pen is selected, it is replaced, and then another pen is selected. So, after replacement the probability of getting a blue is remains the same.
![P(\text{Blue and Blue})=P(\text{Blue})\times P(\text{Blue})](https://tex.z-dn.net/?f=P%28%5Ctext%7BBlue%20and%20Blue%7D%29%3DP%28%5Ctext%7BBlue%7D%29%5Ctimes%20P%28%5Ctext%7BBlue%7D%29)
![P(\text{Blue and Blue})=0.4\times 0.4](https://tex.z-dn.net/?f=P%28%5Ctext%7BBlue%20and%20Blue%7D%29%3D0.4%5Ctimes%200.4)
![P(\text{Blue and Blue})=0.16](https://tex.z-dn.net/?f=P%28%5Ctext%7BBlue%20and%20Blue%7D%29%3D0.16)
Therefore, the value of
is 0.16.