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2 years ago

An unproven statement that is based on observations.

Mathematics

1 answer:

vazorg [7]2 years ago

7 0

Answer:

Hypothesis

Step-by-step explanation:

When people make researches, they make a statement and then go further to either price that statement wrong or right.

Once the statement is proven right, either by virtue of field work or laboratory work, it becomes a theory.

That unproven statement that can either be true or wrong, but baseless because it is yet to be proven is called HYPOTHESIS

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Carly draws quadrilateral JKLM with vertices J(-3,3), K(3,3), L(2,-1),and M(-2, -1). What is the best way to classify the quadri

Trava [24]

Answer:

Trapezoid

Step-by-step explanation:

The points are shown in the attached graph.

You can clearly see from the picture that it is a "Trapezoid".

Trapezoid is basically a quadrilateral (4 sided-figure) that has 1/2 pair of parallel sides.

On the other hand, a parallelogram has 2 pair of parallel sides.

Thus, a parallelogram is a special type of trapezoid where there are 2 pair of parallel sides. But trapezoid need not be a parallelogram.

The picture shows 1 pair of parallel sides, hence it is a trapezoid.

6 0

2 years ago

The measures of the two equal angles of an isosceles triangle are 370 each, then the

e-lub [12.9K]

Answer:

something is incorrect in your question.

Step-by-step explanation:

The sum of all three angles in any triangle is only 180°.

5 0

2 years ago

Find 2 common angles that sum to (17pi/12) 2. Evaluate tan(17pi/12) using the sum identity for tangent.

Dmitry [639]

Note that
$\frac{17 \pi }{12} = \frac{3 \pi }{12} + \frac{14 \pi }{12} = \frac{ \pi }{4} + \frac{7 \pi }{6}$

Note that
$x= \frac{ \pi }{4}:\,\, sin(x) =cos(x)= \frac{1}{ \sqrt{2} },\,tan(x)=1\\x= \frac{7 \pi }{6} :\,\,sin(x)=- \frac{1}{2} ,\,\,cos(x)=- \frac{ \sqrt{3} }{2} ,\,\,tan(x)= \frac{1}{ \sqrt{3} }$

Use the identity
$tan(x+y)= \frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

Therefore
$tan( \frac{17 \pi }{12} )= \frac{1+ \frac{1}{ \sqrt{3} } }{1- \frac{1}{ \sqrt{3} } } = \frac{ \sqrt{3}+1 }{ \sqrt{3}-1} = \frac{( \sqrt{3}+1 )^{2}}{( \sqrt{3}-1 )( \sqrt{3}+1 )} = \frac{3+1+2 \sqrt{3}}{3-1} =2+ \sqrt{3}$

Answer: 2 + √3

8 0

2 years ago

Determine whether the relation describe c as a function of w.

Delicious77 [7]

Answer:

Function:

c = f(w) = 0.49, 0 < w ≤ 1

= 0.70, 1 < w ≤ 2

= 0.91, 2 < w ≤ 3

Step-by-step explanation:

Yes, the relation described can be interpreted as a function.

Here, c is the cost of a mail letter. c depends upon w, which is the weights of the mail letter.

As described in the question, the relation can be expressed as a function.

c can be expressed as a function of w in the following manner:

c(cost of mail) = f(w), where w is the independent variable and c is the dependent variable

c = f(w) = 0.49, 0 < w ≤ 1

= 0.70, 1 < w ≤ 2

= 0.91, 2 < w ≤ 3

where, c is in dollars and w is in ounces.

5 0

3 years ago

Jim's father bought a new car 3 years ago for

Alexus [3.1K]

30% of 50,400 = 30240.

Therefore the percentage loss is 30% over the course of 3 years.

4 0

2 years ago