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2 years ago

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To determine the fee charged to tow a car, a towing company uses the expression 0.7d+ 25, where d is the distance between the pi

ckup point and the drop-off location. If a car is towed 31 miles, how much will the towing company charge the customer? please show your work

1 answer:

babunello [35]2 years ago

3 0

Fee(d) = 0.7d + 25

Then Fee(31 miles) = $25 + ($0.7/mile)(31 miles = $46.70 (answer)

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The image of (6. – 9) after a dilation with respect to the origin is (4,-6). What is the scale factor

qaws [65]

Answer:2/3 or .666666

Step-by-step explanation:

The dilation is a contraction

3 0

3 years ago

What is m∠PTR? a. 12 b. 40 c. 50 d. 140 HELP!!!

kramer

Answer:

m<PTR = 140°

Step-by-step explanation:

First, find the value of x. To find the value of x, derive an equation which you'd use in solving for x.

m<PTQ = (x + 28)°

m<RTS = (2x + 16)°

m<PTQ = m<RTS (vertical opposite angles are congruent)

Therefore:

x + 28 = 2x + 16

Solve for x. Combine like terms

28 - 16 = 2x - x

12 = x

x = 12

Find m<PTQ

m<PTQ = (x + 28)

plug in the value of x

m<PTQ = 12 + 28 = 40°

m<PTR + m<PTQ = 180° (supplementary angles)

m<PTR + 40° = 180° (substitution)

m<PTR = 180 - 40 (subtracting 40 from each side)

m<PTR = 140°

3 0

2 years ago

Add. 7/4+9/-5 wrote your answer as a fraction in simplest form

IgorLugansk [536]

Answer:

7/4 + 9/-5 =

Since the denominator of the second fraction is negative the sign will change from negative to positive

We will get

7/4 - 9/5

First find the LCM

LCM of 4 and 5 is 20

7/4 - 9/5 = 5(7) - 4(9)/ 20

Simplify

We get

35 - 36/20

= -1/20

Hope this helps

5 0

2 years ago

Read 2 more answers

(Sorry forgot to put picture)

Sliva [168]

Answer:

D

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find the price-demand equation for a particular brand television when the demand is 20 TVs per week at $150 per TV, given that t

Alina [70]

Answer:

~ $150=50e^{-0.01()20}$

~ $p(100)=\$127.7$

Step-by-step explanation:

From the question we are told that:

Price of 20TVs per week $P_{20}=\$150$

Marginal price-demand function $p'(x)=-0.5e-0.01x$

Generally the The Marginal price function is mathematically given by

$p'(x)=-0.5e^{-0.01x}$

$p(x)=\int-0.5e^{-0.01x}$

$p(x)=50e^{-0.001x}+C$

Therefore the equation when the demand is 20 TVs per week at $150 per TV

$150=50e^{-0.01()20}$

Giving

$p(x)=50e^{-0.01x}+150-50e^{-0.01(20)}$

Therefore the Price when the demand is 100 TVs per week

$p(100)=50e^{-0.01(100)}+150-50e^{-0.01(20)}$

$p(100)=\$127.7$

7 0

2 years ago