Question

2C4H10 + 13O2 → 8CO2 + 10H2O

Answer 1

Answer:

a) atoms of carbon (C) on each side of the equation - 8

b) atoms of oxygen (O) on each side of the equation - 26

c) atoms of hydrogen (H) on each side of the equation - 20

Explanation:

2C4H10 + 13O2 → 8CO2 + 10H2O

a) Carbon  -

On the left side, number of carbon atoms is derived from 2C4H10 ----> 2 C4

Thus,  there are 8 carbon atoms on left side.

On the right side, number of carbon atoms is derived from 8CO2 ----> 8 C

Thus,  there are 8 carbon atoms on right side.

b) Oxygen

On the left side, number of oxygen  atoms is derived from 13 O2

Thus,  there are $13 * 2 = 26$ oxygen atoms on left side.

On the right side, number of oxygen  atoms is derived from 8CO2 + 10H2O ----> 8 O2 + 10 O

Thus,  there are $8 * 2 + 10 = 16 + 10 = 26$ oxygen atoms on right side.

c) Hydrogen

On the left side,  number of hydrogen atoms is derived from  2C4H10 ----->

2 H 10

Thus,  there are $10 * 2 = 20$ hydrogen atoms on left side.

On the right side,  number of hydrogen atoms is derived from  10H2O ---->  10H2

Thus,  there are $10 *2 = 20$ hydrogen  atoms on right side.

Answer 2

There are 8 carbons, 20 hydrogens, and 26 oxygens.