5 whole and 1/6 hope it help you
There are 75 students in the class. 30*100/40=75
Answer:
The solution of the equation are x = - 1 , y = 0 and z = 3
Step-by-step explanation:
Given three linear equation as :
6 x - y + z = - 3 ......A
4 x - 3 z = - 13 ......B
2 y + 5 z = 15 ......C
Solving eq A and C
I.e 2× (6 x - y + z ) = -3 ×2
or, 12 x - 2 y + 2 z = - 6
So, ( 12 x - 2 y + 2 z ) + ( 2 y + 5 z) = - 6 + 15
Or, 12 x + 7 z = 9 ......D
Solving eq B and D
I.e 3 × ( 4 x - 3 z ) = - 13 × 3
or, 12 x - 9 z = - 39
So, ( 12 x + 7 z ) - ( 12 x - 9 z ) = 9 + 39
or, 16 z = 48
∴ z = 
i.e z = 3
put the value of z in eq D
So, 12 x + 7×3 = 9
Or, 12 x = 9 - 21
or, 12 x = - 12
∴ x = - 
I.e x = - 1
Now, Put The value of z in eq C
or, 2 y + 5 z = 15
or, 2 y + 5 × 3 = 15
Or, 2 y = 15 - 15
or, 2 y = 0
∴ y = 0
Hence The solution of the equation are x = - 1 , y = 0 and z = 3 Answer
The answer is D, on a Graph, no two points can meet when drawn Vertically
Answer:
Given:
Probability that the Yankees wins a game is
P(A) = 0.46
Probability that the Yankees loses a game is
P(A') = 1 - P(A') = 1 - 0.46 = 0.54
Probability that the Yankees scores 5 or more runs in a game is
P(B) = 0.59
Probability that the Yankees scores fewer than 5 runs in a game is
P(B') = 1 - P(B) = 1 - 0.59 = 0.41
Probability that the Yankees wins and scores 5 or more runs is
P(A⋂B) = 0.39
Applying the De Morgan's law, the probability that the Yankees scores fewer than 5 runs and they loses the game would satisfy:
1 - P(A'⋂B') = P(A) ⋃ P(B) = P(A) + P(B) - P(A⋂B)
or
1 - P(A'⋂B') = 0.46 + 0.59 - 0.39
or
1 - P(A'⋂B') = 0.66
=> P(A'⋂B') = 1 - 0.66 = 0.34
Applying the Bayes theorem, the probability that the Yankees would score fewer than 5 runs, given they lose the game:
P(B'|A') = P(A'⋂B')/P(A')
or
P(B'|A') = 0.34/0.54 = 0.630
Hope this helps!
:)