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3 years ago

The sum of two numbers is 7. The larger number is 16 more than 2 times the smaller number. What are the numbers?

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

5 0

The two numbers are 10 and -3.

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Two trucks, 36 feet apart, are towing a large field mower. If the lengths of the tow ropes are 27 feet and 19 feet, find the ang

FrozenT [24]

acute or obtuse yes yay

6 0

3 years ago

Hi guys can u also help me with this, i don’t understand a single thing of it

Bess [88]

HCF=Highest Common Factor-HCF of two or more numbers is the greatest factor that divides the numbers. For example, 2 is the HCF of 4 and 6.
LCM=Least Common Multiple-LCM is the smallest positive number that is a multiple of two or more numbers.

Answers:
1) 6
2) 12
3) 5
4) 3
5) 26
6) 15
7) 88

6 0

1 year ago

Solve the system of linear equations. Check your solution. y=2x-2 <br> y=2x+9

natulia [17]

2X-2=2X+9
Add 2

2X=2X+11
Subract 2X
0= 11

This has no solution to this problem

8 0

3 years ago

The probability that a can of paint contains contamination is 3.23%, and the probability of a mixing error is 2.4%. The probabil

stich3 [128]

Answer:

4.6%.

Step-by-step explanation:

The probability that a can of paint contains contamination(C) is 3.23%

P(C)=3.23%

The probability of a mixing(M) error is 2.4%.

P(M)=2.4%

The probability of both is 1.03%.

$P(C \cap M)=1.03\%$

We want to determine the probability that a randomly selected can has contamination or a mixing error. i.e. $P(C \cup M)$

In probability theory:

$P(C \cup M) = P(C)+P(M)-P(C \cap M)\\P(C \cup M)=3.23+2.4-1.03\\P(C \cup M)=4.6\%$

The probability that a randomly selected can has contamination or a mixing error is 4.6%.

3 0

3 years ago

A triangular course for a canoe race is marked with buoys. The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg

balu736 [363]

<h2>The race is 1.2 miles long</h2>

Step-by-step explanation:

The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi.

$\texttt{Length of first leg = }\frac{3}{10}miles\\\\\texttt{Length of second leg = }\frac{1}{2}miles\\\\\texttt{Length of third leg = }\frac{2}{5}miles$

Now we need to find length of race

$\texttt{Total length = }\frac{3}{10}+\frac{1}{2}+\frac{2}{5}\\\\\texttt{Total length = }\frac{3}{10}+\frac{5}{10}+\frac{4}{10}\\\\\texttt{Total length = }\frac{3+5+4}{10}\\\\\texttt{Total length = }\frac{12}{10}\\\\\texttt{Total length = }1.2miles$

The race is 1.2 miles long

7 0

3 years ago