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jek_recluse [69]
3 years ago
8

What are two steps are necessary to put this equation into standard form x^2 - 3x + 27 =8x- 3

Mathematics
1 answer:
Wittaler [7]3 years ago
7 0

Answer:

you need to bring the 8x over then the -3

Step-by-step explanation:

X^2-3x+27=8x-3

X^2-11x+27=-3

x^2-11x+24

Is that what you are looking for??

Hope that helps feel free to ask more questions


Brainliest??

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Step-by-step explanation:

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The longest side is 24cm and the second-longest side is 20cm what is the length of the shortest side?
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What are the zeros of the quadratic function? f(x)=2x2+x-3
alexgriva [62]

Answer: The zeros of the  quadratic function  are: 5/2+(1/2)*sqrt(31), 5/2-(1/2)*sqrt(31)

                 

Step-by-step explanation:

6 0
3 years ago
Is the sqrt of 1 - sin^2 theta = cos theta true? If so, in which quadrants does angle theta terminate?
Genrish500 [490]

Answer:

Answer: The answer is option B.

Step-by-step explanation:

Here,

We have,

{ \sin }^{2}  theta \: +  {cos}^{2}theta  = 1

{cos}^{2} \: theta  = 1 -  {sin}^{2}  \: theta

cos \: theta =  \sqrt{1 -  { \sin }^{2}theta }

So, it's true; and it lies in quadrant 1 and 4.

The reason according to the "CAST" rule cos theta is in 1st and 3rd quadrant cos theta is positive.

7 0
3 years ago
A line includes the points (-39,49) and (0,0). What is its equation in slope-intercept form?
malfutka [58]

Answer:

The equation in the slope-intercept form will be:

y=-\frac{49}{39}x+0

Step-by-step explanation:

Given the points

  • (-39,49)
  • (0,0)

Finding the slope between the points using the formula

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-39,\:49\right),\:\left(x_2,\:y_2\right)=\left(0,\:0\right)

m=\frac{0-49}{0-\left(-39\right)}

m=-\frac{49}{39}

We know that the point-slope of the line equation is

y-y_1=m\left(x-x_1\right)

substituting m=-\frac{49}{39} and (-39,49)  in the equation

y-y_1=m\left(x-x_1\right)

y-49=\frac{-49}{39}\left(x-\left(-39\right)\right)

Now writing the equation in slope-intercept form

y=mx+b

where m is the slope and b is the y-intercept

y-49=\frac{-49}{39}\left(x-\left(-39\right)\right)

y-49=\frac{-49}{39}\left(x+39\right)

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

y-49=-\frac{49}{39}\left(x+39\right)

\mathrm{Add\:}49\mathrm{\:to\:both\:sides}

y-49+49=-\frac{49}{39}\left(x+39\right)+49

y=-\frac{49}{39}x+0              ∵ y=mx+b

Where

m=-\frac{49}{39} and the y-intercept i.e. b=0

Therefore, the equation in the slope-intercept form will be:

y=-\frac{49}{39}x+0

5 0
3 years ago
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