D = distance from finish line
D= 5 - 1/3x
Distance from the finish line is equal to the distance of the start line from the finish line, minus one third of a km times the number of minutes hes been running.
using given variables; D= 5 - 1/3*3
D=5-3/3
D=5-1
D=4
Let the number<span> be H T O. Ones digit = O Given that. O =10−5 ⇒ O =5. Also is given that tens digit T is 2 </span>more than<span> ones digit O ⇒ tens digit T = O +2=5+2=7. ∴ The </span>number<span> is. H 75. Given also is that "</span>number<span> is </span>less<span> than </span>200<span> and </span>greater than 100<span> " ⇒ H can take value only =1. We get our </span>number<span>as 175.</span>
Answer:
t = 2
Step-by-step explanation:
have a nice day:)
Answer:
-2
Step-by-step explanation:
Just use 6-8 and you will get - 2
Check again with - 2+8 you will get positive 6
