Answer:
J=12. K=3 less than J. 12-3=K
Step-by-step explanation:
f(x) = 4x - x^2
1)
f(4) = 4(4) - 4^2 = 16 - 16 = 0
f(-4) = 4(-4) - (-4)^2 = -16 - 16 = -32
f(4) - f(-4) = 0 - (-32) = 32
2)
f(3/2) = 4(3/2) - (3/2)^2
f(3/2) = 6 - 9/4 = 15/4
√f(3/2) = √(15/4) = √15 / 2
3)
f(x + h) = 4(x + h) - (x + h)^2
= 4x + 4h -(x^2 + 2xh + h^2)
= 4x + 4h -x^2 - 2xh - h^2
f(x - h) = 4(x - h) - (x - h)^2
= 4x - 4h -(x^2 - 2xh + h^2)
= 4x - 4h -x^2 + 2xh - h^2
So
[f(x + h) -f(x - h) ] / 2h
= [4x + 4h -x^2 - 2xh - h^2 - ( 4x - 4h -x^2 + 2xh - h^2 )] / 2h
=( 4x + 4h -x^2 - 2xh - h^2 - 4x + 4h + x^2 - 2xh + h^2 ) / 2h
= (8h - 4xh) / 2h
= 2h(4 -2x) / 2h
= 4 - 2x
Answer: [f(x + h) -f(x - h) ] / 2h = 4 - 2x
Answer:
The radius of a cylinder(r) = √(V / π × h), where V is the volume of a cylinder, h is the height of the cylinder, and π(Pi) is a mathematical constant with an approximate value of 3.14.
Step-by-step explanation:
hope this helps.
9514 1404 393
Answer:
a) $169,234.59
b) $19,234.59
Step-by-step explanation:
The first question you must answer is whether Colleen will earn interest on her first deposit in the first year. That is, does she deposit the money at the first of the year or the end of the year?
The usual "annuity" formula assumes the deposit is at the end of the year, so no interest at all is earned on the last deposit made. If the deposit is at the first of the year, an "annuity due" formula is used, that multiplies the entire ending account value by the annual multiplier, 1.017 in this case.
__
a) Assuming an "annuity", the formula is ...
A = P((1 +r)^t -1)/r . . . . . for annual compounding at rate r for t years
A = $10,000(1.017^15 -1)/0.017 = $169,234.59 . . . . ending balance
__
b) Colleen has made 15 deposits of $10,000, for a total of $150,000, so the amount of interest earned is ...
$169,234.59 -150,000 = $19,234.59 . . . . interest earned
Answer: x=1
Step-by-step explanation:
4 (-x+4）=12
（-4x+16）=12
-4x+16-16 =12-16
-4x/-4 =-4/-4
x=1
I don't know if this is right, please let me know if it is wrong ο(=•ω＜=)ρ⌒☆
