Given that the chip has a dimension of 8 mm by 8 mm which can be written as 0.8 cm by 0.8 cm, is drawn to scale and the dimensions of the plot is 4 cm by 4 cm, the scale of the drawing will be:
0.8 cm is represented by 4 cm
thus;
4 cm rep 0.8 cm
1 cm rep 0.2 cm
The answer is:
1 cm rep 0.2 cm
Answer:
5. f(x) = 10,000 (1.5)^x
Step-by-step explanation:
We would have to multiply the original amount by 1.50^x because the initial amount would be 1, and 50% increase would be .5 so 1.5 and you raise it to the number of years to show the total increase.
Let's test it.
Initial:
10,000
After 1 year
10,000 + (.5*10000)
10,000 + 5000 = 15,000
After 2 years
15,000 + (.5*15000)
15,000 + 7500 = 22,500
Let's try our equation.
f(x) = 10,000 (1.5)^x
x = 2
10,000(1.5)^2
10,000(2.25) = 22,500
The same!
<span>B. f(x) = x^2 + 6x - 7
All you have to do is foil
</span>
From the calculation, the growth rate is 0.88.
<h3>What is the growth rate?</h3>
To find the relative growth rate
P1 = Poe^rt
P2 = Poe^rt
Thus;
1920 = Poe^4r ------ (1)
1966080 =Poe^12r -------(2)
P2/P1 gives;
1966080/1920 = Poe^12r/Poe^4r
1024 = e^12r/e^4r
1024 =e^8r
1024 = (e^r)^8
2^10 = (e^r)^8
e^r = 2^1.25
e^r = 2.38
r = ln(2.38)
r = 0.88
The initial size of the culture is;
1920 = Poe^(0.88 * 4)
Po = 1920/e^(0.88 * 4)
Po = 57
The expression for the exact number of bacteria after t hours is
P(t) = 57e^0.08t
The growth (in bacteria per hour) after 9.5 hours is
P(t) = 57e^(0.88 * 9.5)
P(t) = 243544
For the number to reach 72,000;
72,000 = 57e^0.88t
72,000/57 = e^0.88t
ln 126 = ln[e^0.88t]
4.8 = 0.88t
t = 4.8/0.88
t = 5.5 hours
Learn more about exponential growth;brainly.com/question/13674608
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Answer: Choice D) x can be anything but 13
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Explanation:
The domain of 
is the same as the domain of g(x)
The domain for g(x) is 
saying we can plug in any number we want as long as it's not 13. This is to avoid dividing by zero. The same domain applies for the composite function because
and we can see that we still need to kick out x = 13 from the domain to avoid the division by zero issue.
