What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41
scZoUnD [109]
The original data set is
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}
Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70}
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median.
The value in the 8th slot is 54, so this is the median
Divide the sorted data set into two lists. I'll call them L and U
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).
Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value.
Therefore, Q3 = 62
Answer: 62</span>
To start with, we know there’s a definite amount of parking spaces in all(2,250) and we also know each level(6 in all) had 15 rows of parking spaces.
Equation
A = Parking spots per row
A = 2,250 Divided by(6 levels times 15 rows)
A= 2,250 Divided by 90
A = 25
The correct answer is 25 parking spots per row
To check this answer we can do
25 spots per row, Times 15 rows per level, Times the total amount of levels (6)
= the total amount of parking spots
25*15*6= 2,250
True
This confirms this answer as correct. Hope this helps.
Answer:
Answer below hopes it helps
Step-by-step explanation:
Answer:
-3
Step-by-step explanation:
4(2)-2(2+4)+1=8-2(6)+1=9-12=-3
Answer:
C
Step-by-step explanation:
2(5)^4-1 = 2(5)^3
2*125 = 250 and 250 is the 4th term
