A footpath is to be constructed in a park in the shape of a parallelogram. When a coordinate plane is laid over a map of the par
k, the vertices of the footpath are (-4,2) (8,2) (11,7) and (-1,7). What is the perimeter of this path
2 answers:
I believe the answer is A
Answer: perimeter = 35.66 units
Explanation:
AB=8-(-4)=12
CD=11-(-1)=12
BD=√(11−8)²+(7−2)² = √=34
AC=√(−1−(−4))²+(7−2)² = √=34
Perimeter = AB + CD + BD + AC
perimeter=2×12+2√34 =24+2√34 = 35.66 units
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B your welcome bud, have a good day
