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Natali5045456 [20]
3 years ago
9

Each of the variables t, w, x, y, and z represents a different positive real number. Given the equations below, which of the 4 v

ariables w, x, y, and z necessarily has the greatest value? 1.23w = t 1.01x = t 0.99y = t
Mathematics
1 answer:
alex41 [277]3 years ago
8 0

Answer:

y has the greatest value.

Step-by-step explanation:

1.23w = t

Divide both sides by 1.23.

w=\frac{t}{1.23}

w=0.813t  --- (1)

1.01x = t

Divide both sides by 1.01.

x=\frac{t}{1.01}

x=0.99t --- (2)

0.99y = t

Divide both sides by 0.99.

y=\frac{t}{0.99}

y=1.01t --- (3)

From (1), (2) and (3), it is clear that y has the greatest value.

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5 Consider this system of equations:<br> 5x + y = -2<br> 2x - 2y=4
Ilia_Sergeevich [38]

Answer:

x  = 0

  y  = -2

Step-by-step explanation:

The given system of equation are:

   5x + y = -2

   2x - 2y = 4  

The problem here is to find x and y from the expression

   5x + y = -2     ----- i

   2x - 2y = 4    ---- ii

 So;

i x 2 :  10x + 2y  = -4     ----  iii

ii x 5 :  10x - 10y  = 20    ----- iv

   iii - iv;   12y  = -24

                  y  = -2

    Now find x;

             5x + y  = -2

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7 0
3 years ago
House of Mohammed sells packaged lunches, where their finance department has established a
blagie [28]

The revenue function is a quadratic equation and the graph of the function

has the shape of a parabola that is concave downwards.

The correct responses are;

  • (a) <u>R = -x² + 82·x</u>
  • (b) <u>$1,645</u>
  • (c) The graph of <em>R</em> has a maximum because the <u>leading coefficient </u>of the quadratic function for <em>R</em> is negative.
  • (d)  <u>R = -1·(x - 41)² + 1,681</u>
  • (e) <u>41</u>
  • (f) <u>$1,681</u>

Reasons:

The given function that gives the weekly revenue is; R = x·(82 - x)

Where;

R = The revenue in dollars

x = The number of lunches

(a) The revenue can be written in the form R = a·x² + b·x + c by expansion of the given function as follows;

R = x·(82 - x) = 82·x - x²

Which gives;

  • <u>R = -x² + 82·x </u>

<em>Where, the constant term, c = 0</em>

(b) When 35 launches are sold, we have;

x = 35

Which by plugging in the value of x = 35, gives;

R = 35 × (82 - 35) = 1,645

  • The revenue when 35 lunches are sold, <em>R</em> = <u>$1,645</u>

(c) The given function for <em>R</em> is R = x·(82 - x) = -x² + 82·x

Given that the leading coefficient is negative, the shape of graph of the

function <em>R</em> is concave downward, and therefore, the graph has only a

maximum point.

(d) The form a·(x - h)² + k is the vertex form of quadratic equation, where;

(h, k) = The vertex of the equation

a = The leading coefficient

The function, R = x·(82 - x), can be expressed in the form a·(x - h)² + k, as follows;

R = x·(82 - x) = -x² + 82·x

At the vertex, of the equation; f(x) = a·x² + b·x + c,  we have;

\displaystyle x = \mathbf{-\frac{b}{2 \cdot a}}

Therefore, for the revenue function, the x-value of the vertex, is; \displaystyle x = -\frac{82}{2 \times (-1)} = \mathbf{41}

The revenue at the vertex is; R_{max} = 41×(82 - 41) = 1,681

Which gives;

(h, k) = (41, 1,681)

a = -1 (The coefficient of x² in -x² + 82·x)

  • The revenue equation in the form, a·(x - h)² + k is; <u>R = -1·(x - 41)² + 1,681</u>

(e) The number of lunches that must be sold to achieve the maximum revenue is given by the x-value at the vertex, which is; x = 41

Therefore;

  • The number of lunches that must be sold for the maximum revenue to be achieved is<u> 41 lunches</u>

(f) The maximum revenue is given by the revenue at the vertex point where x = 41, which is; R = $1,681

  • <u>The maximum revenue of the company is $1,681</u>

Learn more about the quadratic function here:

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