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<h3>Answer : y = ⅚x - 3</h3>
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<h3>Known</h3>
x1 = 6
y1 = 2
x2 = (-6)
y2 = (-8)
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<h3>Question</h3>
Equation of the line (y = mx + c)
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<h3>Way to do</h3>
#First, you find the gradient (m)
#Now use the formula of equation of the line
y - y1 = m(x - x1)
y - 2 = ⅚(x - 6)
y - 2 = ⅚x - 5
y = ⅚x - 5+2
y = ⅚x - 3
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Answer:
Step-by-step explanation:
The ratio of 6:30 would be equivalent to it.
SA=2(lw+wh+lh) This is the formula for finding the surface area of a rectangular prism, where SA is surface area, l is length, w is width, and h is height.
208=2(lw+wh+lh)
104=lw+wh+lh Here, I divided both sides by 2 to get ride of the 2.
Now, I used prime factorization to find out all the prime factors of 104, which are 2, 2, 2, and 13. Since rectangular prisms only have 3 dimensions, I needed to combine two of the prime factors. In this case, I can either combine 2 of the 2s to get 2, 4, and 13 or I can combine 13 with one of the 2s to get 26, 2, and 2.
If my dimensions were 2, 4, and 13...
my surface area would be 172 sq cm.
If my dimensions were 2, 2, and 26...
my surface area would be 208 sq cm.
Hence, the width of the rectangular prism when the surface area is 208 square centimeters can be either 2 or 26.
1/2sqrt((x_1^2+y_1^2)(x_2^2+y_2^2))
The area of a triangle is equal to 1/2bh (one half base times height). Since this is a right triangle, the base and height are the two legs connected to the 90* angle. To find the values of these sides, we will use Pythagorean Theorem, root a squared plus b squared.
Short leg: <x(1),y(1)>
This leg can be seen as the hypotenuse of an invisible right triangle. The x value, x(1), is how far over the x value has gone from the origon at x=0. Imagine a leg alone the x-axis, going from (0,0) to (x(1),0). The y value of the point, y(1), works the same way. This leg will go from our previous mark at (x(1),0) to the point (x(1),y(1)). This shows that the short leg of the main triangle is the hypotenuse, with a height of y(1) and base of x(1). Pythagoreum Theorem shows that the length of this leg is equal to sqrt(x_1^2+y_1^2).
Long leg: <x(2), y(2)>
The same process works here, giving us sqrt(x_2^2+y_2^2).
Now for the area, we have the b and h values. Our equation reads 1/2sqrt(x_1^2+y_1^2)sqrt(x_2^2+y_2^2).
But we can simplify this (yay). The two square roots can be written together as sqrt((x_1^2+y_1^2)(x_2^2+y_2^2))
So the correct answer is 1/2sqrt((x_1^2+y_1^2)(x_2^2+y_2^2))
