I suspect 4/2 should actually be 4/3, since 4/2 = 2, while 4/3 would make V the volume of a sphere with radius r. But I'll stick with what's given:
In Mathematica, you can check this result via
D[4/2*Pi*r^3, r]
5(6*3) = 5(18) = 90
(5*6)3 = (30)3 = 90
The answer is the same by the associative law.
To get the probability of selecting a person who is a
democrat and is favour to the issue, let us first calculate for the portions in
each party who is favour on the issue.
p (rep & favour) = 0.4 * 0.3 = 0.12
p (dem & favour) = 0.6 * 0.7 = 0.42
Therefore the total portions who are favour is:
p (favour) = 0.12 + 0.42 = 0.54
Hence the probability is:
P (dem & favour) = 0.42 / 0.54 = 0.7778 = 0.78
Therefore there is about 78% probability that the person
selected who is favour to the issue is a democrat.
Answer:
It is either A. or C.
Step-by-step explanation:
Answer:
Step-by-step explanation:
1) From AP to PB
we get , from part to part that ,
AP=(1/2)*PB or
PB = 2*AP
2) from part to whole,
AP to AB, we get
AP = (1/3)*AB
or AB = 3*AP
