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4 years ago

Volume of a pyramid 10 feet by 10 feet base and height of 8.5 feet

1 answer:

5 0

The formula for the volume of a pyramid is: Volume=(1/3)*(Area of the base)*(Height of the pyramid) You stated that the pyramid has a 10 by 10 base, so the "area of the base" is 100 squared feet. Also, you stated that the "height of the pyramid" is 8.5 feet. So, Volume=(1/3)(100 squared feet)(8.5 feet) V=(1/3)(850 cubic feet) V=283.33333..... cubic feet

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Answer:

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3 years ago

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Rewrite the equation by completing the square. 4x2 + 28x + 49 = 0 (x+) =

Vlada [557]

Answer: x = - 3.5

Step-by-step explanation:

Rewrite the equation by completing the square.

4x2 + 28x + 49 = 0

Completing the square method :

Divide through by the Coefficient of x^2

x^2 + 7x + (49/4) = 0

a = 1, b = 7, c = 49/4

Move c to the right side of the equation

x^2 + 7x = - 49/4

Complete the square on the left hand side by squaring its half of the x term

(7/2)^2 = (49/4)

Add the output to both sides of the equation

x^2 + 7x + (49/4) = - (49/4) + (49/4)

(x + 7/2)^2 = 0

Square root of both sides

x + 7/2 = 0

x = - 7/2

x = - 3.5

4 0

3 years ago

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

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3 years ago

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Alex17521 [72]

Answer:mean

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3 years ago

How do you write 79% as a fraction or whole number in simplest form?

Nikolay [14]

79% = 0.79= 79/100
(not sure if this is what you meant?)

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4 years ago

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