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Anit [1.1K]
3 years ago
12

A municipal issuer official has lost her re-election campaign and has just left elected office. She is soliciting political cont

ributions in a "clean-up" campaign to settle her campaign debt. Which statement is TRUE about an MFP that wishes to contribute $500 to the "clean-up" campaign?
Business
1 answer:
Sindrei [870]3 years ago
5 0

Answer: Because the issuer official no longer holds elected office, the contribution limits of Rule G-37 do not apply.

Explanation:

Rule G-37 is a way to ensure that Municipal Issuers are not unduly influenced by those who donated to their campaigns to get into a position to become Municipal Issuers.

It prohibites for 2 years, Municipal Finance Professionals (MFP) amongst others from engaging in municipal securities business with a Municipal issuer.

An exception however, is that if the MFP is entitled to a vote for the Official in question, they can donate no more than $250 per election.

Seeing as the Municipal Issuer Officer has lost her position, the MFP need not worry about this $250 limit as it no longer applies to her. The MFP is free to donate $500 to the "clean-up" campaign.

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Sales revenue$ 4,000Purchases of direct materials$ 400Direct labor$ 450Manufacturing overhead$ 620Operating expenses$ 650Beginni
dlinn [17]

Answer:

The correct answer is D: $1900

Explanation:

Giving the following information:

Sales revenue$ 4,000

Purchases of direct materials$ 400

Direct labor$ 450

Manufacturing overhead $ 620

Operating expenses$ 650

Beginning raw materials inventory$ 200

Ending raw materials inventory$ 180

Beginning work in process inventory$ 320

Ending work in process inventory$ 410

Beginning finished goods inventory$ 250

Ending finished goods inventory$ 200

First, we need to calculate the cost of goods manufactured:

cost of goods manufactured= beginning work in process + direct materials + direct labor + manufacturing overhead - ending work in process

Direct materials= beginning inventory + purchase - ending inventory= 200 + 400 - 180= 420

cost of goods manufactured= 320 + 420 + 450 + 620 - 410= $1400

Now, we can calculate the cost of goods sold:

COGS= beginning finished inventory + cost of goods manufactured - ending finished goods

COGS= 250 + 1400 - 200= 1450

Operating income= sales  - COGS - operating expenses

Operating income= 4000 - 1450 - 650= $1900

3 0
3 years ago
The publisher of an economics textbook finds that, when the book's price is lowered from $70 to $60, sales rise from 10,000 to 1
ankoles [38]

Answer:

Price elasticity of demand = 2.6

Explanation:

Given:

Old price (P0) = $70

New price (P1) = $60

Old sales (Q0) = 10,000 units

New sales (Q1) = 15,000 units

Computation of Price elasticity of demand(e):

Midpoint method

e=\frac{\frac{Q1-Q0}{\frac{Q1+Q0}{2} } }{\frac{P1-P0}{\frac{P1+P0}{2} } }

By putting the value:

e=\frac{\frac{10,000-15,000}{\frac{10,000+15,000}{2} } }{\frac{60-70}{\frac{60+70}{2} } }\\e=\frac{\frac{-5,000}{\frac{25,000}{2} } }{\frac{-10}{\frac{130}{2} } }\\

e=\frac{\frac{-5,000}{12,500} }{\frac{-10}{65} }

e =  2.6

7 0
3 years ago
A year after the equine safety program was conducted in a riding stable, the volunteers remembered that they must always cross-t
Rasek [7]
The answer is a it was successful
8 0
2 years ago
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Answer:

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Explanation:

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8 0
2 years ago
Larry is a hard-working college freshman. One Saturday, he decides to work nonstop until he has answered 200 practice problems f
OverLord2011 [107]

Answer:

  • The marginal gain from Larry's second hour of work is 60 problems
  • The marginal gain from Larry's fourth hour of work is 20 problems
  • The best combination is 1 hour of working problems + 3 hours of reading

Explanation:

To get the <em><u>marginal gain</u></em> we subtract from the latest hour, in this case the second hour (140), the production from the previous hour (80). 140-80=60. <em>It's always the same, the latest minus the previous one.</em>

So let's do the same for the fourth hour:

Noon................200 problems

minus

11:00 AM..........180 problems

200-180= 20 problems

Now to know how many hours he should spend working on problems and reading, let's compare:

An hour of reading equals to 70 problems made; (because working on 70 problems raises a student’s exam score by about the same amount as reading the textbook for 1 hour).

hours of working problems         problems solved

0............................................................0

1.............................................................80

2............................................................140

3............................................................180

hours reading                    problems equivalent to hours read

4...............................................(4*70)=280

3...............................................(3*70)=210

2...............................................(2*70)=140

1................................................(1*70)=70

finally let's add up the two combinations (0 and 4, 1 and 3, 2 and 2, 3 and 1)

0 and 4_______________0+280= 280

1 and 3________________80+210=290

2 and 2_______________140+140=280

3 and 1________________180+70=250

<em>And the best combination is 1 hour of working problems + 3 hours of reading=</em><em>290</em>

3 0
3 years ago
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