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Paladinen [302]
3 years ago
14

3(3y-4)=51 solve for y

Mathematics
2 answers:
mr Goodwill [35]3 years ago
8 0

Answer:

y=7

Step-by-step explanation:

[in picture]

Luba_88 [7]3 years ago
4 0

Answer:

y = 7

Step-by-step explanation:

3 × (3y - 4) = 51 multiply 3 with inside the parenthesis

9y - 12 = 51 add like terms

9y = 51 + 12

9y = 63

y = 7

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The area of Taylor’s square bedroom is 256 feet squared, what is the length of any side wall in his bedroom?
MAXImum [283]
The length of one side of his bedroom would be 16 feet.

The formula for area of a square is length x width and all four sides of a square are equal in length.

In this case 16x16 is equal to 256
6 0
3 years ago
I want to know the answers to the ones circled
LenaWriter [7]

Hello! I will do my best to help you understand and receive the answers.

Let's begin with our first question..

15.) Dao has 2 3/8 pounds of hamburger meat. He is making 1/4 pound burgers. How many burgers can he make?

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Your final answer should be : Dao can make 3 hamburgers total.

I would answer the next question, but I believe from this information above you can try and figure it out. If you are still stuck, message  me and i can help you from there.


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4 0
4 years ago
Can I get help with finding the Fourier cosine series of F(x) = x - x^2
trapecia [35]
Assuming you want the cosine series expansion over an arbitrary symmetric interval [-L,L], L\neq0, the cosine series is given by

f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx

You have

a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx
a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}
a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)
a_0=-\dfrac{2L^2}3

a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}

and so

a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}

So the cosine series for f(x) periodic over an interval [-L,L] is

f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx
4 0
3 years ago
One pump can empty a pool in 4 days, whereas a second pump can empty the pool in 10 days. How long will it take the two pumps, w
gtnhenbr [62]

Answer:

20/7 days (just less than 3 days)

Step-by-step explanation:

Recall that (1 job) = (rate)(time), so time = (1 job) / (rate).

Set up and solve the following equation:

  1 job

------------------------------- = time required for 2 pumps working together

1 job         1 job

---------- + -------------

4 days      10 days

This comes out to:

              1 job

------------------------------------------- = time required

10 job-days      4 job-days

------------------ + -----------------

   40 days           40 days

or:

    1 job

-------------------- = (40/14) days, or 20/7 days (just less than 3 days)

14 job·days

-----------------

   40 days  

7 0
3 years ago
Plz help i will mark brainlest
11111nata11111 [884]

Answer:

a,b and dcbecause it equals 1

Step-by-step explanation:

you have to find something that is gonna divide by itself to get a postive number, so d wont work bc it would be 24 divided by 25

8 0
3 years ago
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