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JulsSmile [24]
2 years ago
13

What is NKM?? I don’t know what to do!

Mathematics
1 answer:
Allushta [10]2 years ago
6 0
HUH???????????????????
You might be interested in
(0,65-3,21)por(-8,12)=?
PIT_PIT [208]

Answer:  =20,7872

Step-by-step explanation:

For this exercise it is important to remember the multiplication of signs. Notice that:

(+)(+)=+\\\\(-)(-)=+\\\\(-)(+)=-\\\\(+)(-)=-

In this case you have the following expression given in the exercise:

(0,65-3,21)(-8,12)

Then you can follow the steps shown below in order to solve it:

Step 1: You must solve the subtraction of the numbers 0,65 and 3,21. Then:

=(-2,56)(-8,12)

Step 2: Now you must find the product of the decimal numbers above. In order to do that you must multiply the numbers.

(As you can notice, both are negative, therefore you know that the product will be positive).

Then, you get that the result is the following:

 =20,7872

5 0
2 years ago
What is the slope of (8,3) and (-4,-6)?
Nonamiya [84]

<u>Answer:</u> The slope of the line formed by these two points is \frac{3}{4}

<u>Step-by-step explanation:</u>

To calculate the slope, we use the formula:

Slope=\frac{y_2-y_1}{x_2-x_1}

For the coordinates given:

x_1=8\\y_1=3\\x_2=-4\\y_2=-6

Putting values in above equation, we get:

Slope=\frac{(-6-3)}{(-4-8)}\\\\Slope=\frac{-9}{-12}\\\\Slope=\frac{3}{4}

Hence, the slope of the line formed from these two coordinates is  \frac{3}{4}

8 0
3 years ago
-2(x-9)=-24 what is x?
icang [17]
The answer is x= 21.
8 0
3 years ago
Read 2 more answers
The term "freshman 15" refers to the claim that college students typically gain 15lbs during freshman year at college. Assume th
Viefleur [7K]

The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%

<h3>What is Probability ?</h3>

Probability is defined as the likeliness of an event to happen.

Let X be a random variable that shows the term "freshman 15" that claims that students typically gain 15lb during their freshman year at college.

It is given that

X follows is a normal distribution with a mean of 2.1 lb (μ) and a standard deviation (σ)  of 10.8 lb.

Population Mean (μ) = 2.1

Population Standard Deviation (σ) = 10.8

We need to compute Pr(X≥15). The corresponding z-value needed to be computed is:

\rm Z_{lower} = \dfrac{ X_1 -\mu }{\sigma}\\\\Z_{lower} = \dfrac{ 15-2.1 }{10.8}\\\\\\Z_{lower} = 1.19

Then the probability is given as

\rm Pr(X \geq 16 ) = Pr (\dfrac{X -21}{10.8} \geq \dfrac{15-21}{10.8})\\\\= Pr (Z \geq \dfrac{15-2.1}{10.8}\\\\= Pr (Z\geq 1.19)\\\\ = 0.1162

Pr(X≥15)=0.1162. (11.6%)

The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%

To know more about Probability

brainly.com/question/11234923

#SPJ1

3 0
2 years ago
Select the property of equaliity used to arrive at the conclusion. if x=3 then x2=3x
zavuch27 [327]
3x2=3x3

9=9

hope this helps!


4 0
3 years ago
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