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charle [14.2K]
3 years ago
14

Equivalent to(3-5b)2

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
6 0

Answer:

6-10b

Step-by-step explanation:

You might be interested in
Bane currently uses a ratio of Venom to water, 8:31. if Bane used 16 cups if Venom, how many cups water does he need?
san4es73 [151]

Answer:

62 cups

Step-by-step explanation:

This ratio problem can easily be solved if we write 2 fractions and equate to each other.

The leftside fraction would be the "ratio", that is 8/31.

The right side fraction would be the actual amount, that is:

16 cups for venom

x cups for water

We need to find x. Remember to keep Venom on top (numerator) and water on bottom (denominator). Let's write the ratios (fractions) and equate and cross multiply and solve:

\frac{8}{31}=\frac{16}{x}\\8x=16*31\\8x=496\\x=\frac{496}{8}\\x=62

So,

Bane needs 62 cups of water

3 0
3 years ago
The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y– 1 =1/4 (x – 12). What is the sta
Lorico [155]

Answer:

x-4y = 8

Step-by-step explanation:

y– 1 =1/4 (x – 12)

Multiply each side by 4

4y -4 = x-12

Subtract x from each side

-x +4y -4 = -12

Add 4 to each side

-x+4y -4+4 = -12 +4

-x+4y = -8

Multiply by -1

x-4y = 8

5 0
2 years ago
2+2? I don’t know the answer I am in first grade
geniusboy [140]

Answer: 4

Step-by-step explanation: I don't think you are in 1st grade but if you are here you go.

7 0
3 years ago
Read 2 more answers
The question is below
givi [52]
That angle would also be 45
5 0
2 years ago
Read 2 more answers
Lots of 40 components each are deemed unacceptable if they contain 3 or more defectives. The procedure for sampling a lot is to
MrRissso [65]

Answer:

The probability of founding exactly one defective item in the sample is P=0.275.

The mean and variance of defective components in the sample are:

\mu=0.375\\\\\sigma^2=0.347

Step-by-step explanation:

In the case we have a lot with 3 defectives components, the proportion of defectives is:

p=3/40=0.075

a) The number of defectives components in the 5-components sample will follow a binomial distribution B(5,0.075).

The probability of having one defective in the sample is:

P(k=5)=\binom{5}{1}p^1(1-p)^4=5*0.075*0.925^4=0.275

b) The mean and variance of defective components in the sample is:

\mu=np=5*0.075=0.375\\\\\sigma^2=npq=5*0.075*0.925=0.347

The Chebyschev's inequality established:

P(|X-\mu|\geq k\sigma)\leq \frac{1}{k^2}

6 0
3 years ago
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