Answer:
I think you missed something of question take a look at it
Answer:
A. 2 speciation events and 5 extinctions
B. 5 speciation events and 1 extinction
Explanation:
As we can see from the diagram, there were only 2 ,aim speciation events for lineage A. The extinction events were 5 for the A lineage. Hence, as the extinction event was more rapid than the speciation event so lineage A contains only one species.
On the other hand, the diagram shows that for lineage B there were 5 speciation events and just 1 extinction event. Hence, the number of species in lineage B were more at the time zero as just one extinction had occurred.
Answer:
All of the other answer choices suggest the presence of a multipass transmembrane protein.
Explanation:
The primary sequence contains stretches of polar and nonpolar amino acids, suggesting an amphipathic design.
This one could be, because of the presence of polar an nonpolar aminoacids. The phospholipids membrane have the same construction.
The protein has windows of the primary sequence with positive hydropathy values separated by windows of the primary sequence with negative hydropathy values.
The same here, having pieces of positive and negative hidropathy can be a sign of transmembrane protein.
The protein isolates with the membrane fraction of the cell rather than the cytoplasmic fraction of the cell.
This is discribing you a transmembrane protein