Answer:
0.5
Explanation:
According to Hardy-Weinberg equilibrium p2+2pq+q2=1 (p+q=1)
p2 is frequency of the dominant homozygous genotype
2pq is the frequency of the heterozygous genotype
q2 is the frequency of the recessive homozygous genotype
In the example above 80 chickens have bare legs (ff)-recessive homozygous which means that the frequency of that genotype is 80/240+80=0.25 (q2), frequency of the recessive allele is
=0.5. This means that the frequency of the dominant allele (p) is 1-0.5=0.5
So, the frequency of the heterozygous genotype (2pq) is 2*0.5*0.5=0.5
The frequency of the dominant homozygous genotype is p2=0.25
Answer:
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Explanation:
iwe have that
x + (2x + 40) + (3x – 50) = 15,002
Reorder the terms:
(x+2x+3x)+(40-50)=15,002
Combine like terms:
x+2x+3x=6x
40-50=-10
6x-10=15,002
adds +10 both sides
6x-10+10=15,002+10
Combine like terms:
-10+10=0
15,002+10=15,012
6x=15,012
we have that
x + (2x + 40) + (3x – 50) = 15,002
Reorder the terms:
(x+2x+3x)+(40-50)=15,002
Combine like terms:
x+2x+3x=6x
40-50=-10
6x-10=15,002
adds +10 both sides
6x-10+10=15,002+10
Combine like terms:
-10+10=0
15,002+10=15,012
6x=15,012
we have that
x + (2x + 40) + (3x – 50) = 15,002
Reorder the terms:
(x+2x+3x)+(40-50)=15,002
Combine like terms:
x+2x+3x=6x
40-50=-10
6x-10=15,002
adds +10 both sides
6x-10+10=15,002+10
Combine like terms:
-10+10=0
15,002+10=15,012
6x=15,012
we have that
x + (2x + 40) + (3x – 50) = 15,002
Reorder the terms:
(x+2x+3x)+(40-50)=15,002
Combine like terms:
x+2x+3x=6x
40-50=-10
6x-10=15,002
adds +10 both sides
6x-10+10=15,002+10
Combine like terms:
-10+10=0
15,002+10=15,012
6x=15,012
Answer:
Explanation:
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no positive things happened till now
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Answer:
Passing through clay beds filters groundwater, purifying out soil, or organic materials, and contaminants to leave behind pure water that fills up aquifers.
Explanation:
I hope this help you .
