T the woman row part way at an angle Θ to the diameter,
<span>and walk along the arc for the rest of the way. </span>
<span>since the triangle on the diameter is right angled, angle subtended at the centre by the arc walked will be 2Θ </span>
<span>distance rowed is 2rcosΘ = 4cosΘ </span>
<span>and length of the arc jogged = r•2Θ = 4Θ, Θ in radians, </span>
<span>so T(Θ) = 4cosΘ/5 + 4Θ/10 </span>
<span>= 0.8cosΘ + 0.4Θ </span>
<span>T'(Θ) = -0.8sinΘ + 0.4 </span>
<span>but T"(Θ) = -0.8cosΘ, so setting T'(Θ) to 0 will give a MAXIMA </span>
<span>so minimum time has to be at one of the 2 extrema (Θ=0 or pi/2) </span>
<span>T(0) = 0.8 </span>
<span>T(pi/2) = 0.4pi/2, < T(0) </span>
<span>so least time = 0.4pi/2 hrs </span>
Answer: i cant see the question, its too pixelated
Step-by-step explanation:
Answer:
335 mm²
Step-by-step explanation:
This will be so easy, that you can do it in the future by yourself!
Okay let's start by splitting this figure, the easiest way seems to be by cutting off that little part, you know what just let me show a picture.
Okay you shuold be able to see the picture, so the small square has an area of 20, since 5 times 4 is 20 mm! The larger square has an area of 315!
How did I find this? Take that small 10mm in the side and add it to 5mm, that would be 15. 15 times the bottom the width, it would be 15 * 21. 15 times 21 is equal to 315.
Now, we add both those areas together, to get ourselves a nice little 335 mm²
I hope that helped, have a great day!!