Question

What is the value of x in the equation below?

Answer 1

$remember$
$ln(a^b)=bln(a)$
$ln(e)=1$
$so$
$ln(e^x)=xln(e)=x$


$1+2e^{x+1}=9$
$minus \space\ 1 \space\ both \space\ sides$
$2e^{x+1}=8$
$divide \space\ both \space\ sides \space\ by \space\ 2$
$e^{x+1}=4$
$take \space\ ln \space\ of \space\ both \space\ sides$
$ln(e^{x+1})=ln(4)$
$(x+1)ln(e)=ln(4)$
$x+1=ln(4)$
$minus \space\ 1 \space\ from \space\ both \space\ sides$
$x=ln(4)-1$
$answer \space\ is \space\ C=ln(4)-1$

Answer 2

remember

ln(a^b)=bln(a)

ln(e)=1

so

ln(e^x)=xln(e)=x

1+2e^{x+1}=9

minus \space\ 1 \space\ both \space\ sides

2e^{x+1}=8

divide \space\ both \space\ sides \space\ by \space\ 2

e^{x+1}=4

take \space\ ln \space\ of \space\ both \space\ sides

ln(e^{x+1})=ln(4)

(x+1)ln(e)=ln(4)

x+1=ln(4)

minus \space\ 1 \space\ from \space\ both \space\ sides

x=ln(4)-1

answer \space\ is \space\ C=ln(4)-1