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stira [4]
3 years ago
6

What is the value of x in the equation below?

Mathematics
2 answers:
belka [17]3 years ago
5 0
remember
ln(a^b)=bln(a)
ln(e)=1
so
ln(e^x)=xln(e)=x


1+2e^{x+1}=9
minus \space\ 1 \space\ both \space\ sides
2e^{x+1}=8
divide \space\ both \space\ sides \space\ by \space\ 2
e^{x+1}=4
take \space\ ln \space\ of \space\ both \space\ sides
ln(e^{x+1})=ln(4)
(x+1)ln(e)=ln(4)
x+1=ln(4)
minus \space\ 1 \space\ from \space\ both \space\ sides
x=ln(4)-1
answer \space\ is \space\ C=ln(4)-1
diamong [38]3 years ago
4 0

remember

ln(a^b)=bln(a)

ln(e)=1

so

ln(e^x)=xln(e)=x



1+2e^{x+1}=9

minus \space\ 1 \space\ both \space\ sides

2e^{x+1}=8

divide \space\ both \space\ sides \space\ by \space\ 2

e^{x+1}=4

take \space\ ln \space\ of \space\ both \space\ sides

ln(e^{x+1})=ln(4)

(x+1)ln(e)=ln(4)

x+1=ln(4)

minus \space\ 1 \space\ from \space\ both \space\ sides

x=ln(4)-1

answer \space\ is \space\ C=ln(4)-1


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