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3 years ago

Could you please help me with all of the questions

Mathematics

1 answer:

belka [17]3 years ago

8 0

264/9= 29.3 < 458/5= 91.6

2805/4= 701.25 > 3952/6= 598.6

719/8= 89.875 > 176/8= 88

2501/4= 625.25 > 1486/3= 495.3

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(-4,-3) and (4,3) distance formula

TEA [102]

Answer:

The answer is 10

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3 years ago

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Please answer the question from the attachment.

xenn [34]

Change it into improper fraction to make it easier or just solve it as is.
= $3\frac{5}{8}$ - $2\frac{7}{8}$
= $\frac{29}{8}$ - $\frac{23}{8}$
= $\frac{6}{8}$ = $\frac{3}{4}$
OR
= $3 \frac{5}{8}$ - $2 \frac{7}{8}$
divide it to two parts:
3-2=1 and $\frac{5}{8}$ - $\frac{7}{8}$ = $\frac{-2}{8}$
$1\frac{-2}{8}$ ⇒(1×8-2=6)
= $\frac{6}{8}$ = $\frac{3}{4}$

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3 years ago

The center of a circle is located at (3, 8), and the circle has a radius that is 5 units long. What is the general form of the e

babymother [125]

The answer is A. To understand that, you need to put it in order by the x's and the y's to get x^2-6x + y^2-16y = -48. Now complete the square on both the x and the y terms to get (x^2-6x+9) +(y^2-16y+64) = -48+9+64. Rewriting that in vertex form on the left and doing the math on the right gives you
(x-3)^2 + (y-8)^2 = 25, which shows you a center of (3,8) and a radius of 5.

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3 years ago

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Determine whether each integral is convergent or divergent. If it is convergent evaluate it. (a) integral from 1^(infinity) e^(-

AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

$\int_1^{\infty} e^{-2x} dx=\left[-\frac{e^{-2x}}{2}\right]_1^{\infty}\\\\\int_1^{\infty} e^{-2x} dx=-\frac{e^{-\infty}}{2}+\frac{e^{-2}}{2}\\\\\int_1^{\infty} e^{-2x} dx=\frac{e^{-2}}{2}\\$

So, this integral is convergent.

$\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\$

So, this integral is divergent.

$\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\$

So, this integral is divergent.

4 0

3 years ago

The width of the rectangle is 0.6 meters less than the length. The perimeter of a rectangle is 60.8 meters. Find the dimensions

Anvisha [2.4K]

Answer:

14+=+2L+%2B+2%28L-3%29 Simplify and solve for L

14+=+2L+%2B+2L+-+6 Combine like-terms.

14+=+4L-6 Add 6 to both sides.

20+=+4L Divide both sides by 4.

5+=+L The length is 5 meters.

W+=+L-3

W+=+5-3

W+=+2meters.

The width is 2 meters.

P+=+2L%2B2W

P+=+2%285%29%2B2%282%29

P+=+10%2B4

P+=+14meters.

Step-by-step explanation:

4 0

3 years ago