Brainliest Giveaway!! Also gives all of my points.!!
2 answers:
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Answer:
294 cars.
Step-by-step explanation:
Let x be the number of cars and y be the number of trucks.
We have been given that the first dealership sells a total of 164 cars and trucks. We can represent this information as:
The second dealership sells twice as many cars and half as many trucks as the first dealership. So the number of cars sold by 2nd dealership will be 2x and number of trucks sold by 2nd dealership will be y/2.
Further, the 2nd dealership sold a total of 229 cars and trucks. We can represent this information as:
We can see that total number of cars sold on two dealerships will be .
We will use substitution method to solve for x. From equation (1) we will get,
Substituting this value in equation (2) we will get,
Now let us have a common denominator.
Upon multiplying both sides of our equation by 2 we will get,
Therefore, the total number of cars sold by two dealerships is 294.
If a quadrilateral is a rhombus then:
i) all its sides have equal length,
and
ii) the 2 diagonals are perpendicular and bisect each other.
The 2 diagonals of rhombus JKLM intersect at N.
Then m(MNJ)=90°, |JN|=4 and |NM|=3 units
thus, by the Pythagorean theorem,
The perimeter of the rhombus is 4*5 units=20 units.
Answer: 20 units
i) all its sides have equal length,
and
ii) the 2 diagonals are perpendicular and bisect each other.
The 2 diagonals of rhombus JKLM intersect at N.
Then m(MNJ)=90°, |JN|=4 and |NM|=3 units
thus, by the Pythagorean theorem,
The perimeter of the rhombus is 4*5 units=20 units.
Answer: 20 units