Question

What is the probability of rolling a three on the first die and a two on the second die?

Answer 1

The two rolls of the number cube are independent events because
the result of 1 roll does not affect the result of the other roll.
To find the probability of two independent events, we first find
the probability of each event, then we multiply the probabilities.
We can find the probability of an event using the following ratio:
number of favorable outcomes/total number of outcomes
Since there is only one way to roll a 3 and there are six
possible outcomes, 1, 2, 3, 4, 5, and 6, the probability of rolling a 3 is 1/6.
Since there is also only one way to roll a 2 and there are
six possible outcomes, the probability of rolling a 2 would be 1/6.
Now we multiply the probabilities.
1/6 x 1/6 is 1/36.
So the probability of rolling a 3 and a 2 is 1/36.

Answer 2

Answer:

$\frac{1}{36}$

Step-by-step explanation:

Probability of rolling a three = $\frac{1}{6}$

Probability of rolling a two = $\frac{1}{6}$

Probability of rolling a three on the first die and two on the second = $\frac{1}{6}$ × $\frac{1}{6}$

= $\frac{1}{36}$