Question

Need help with these 2 problems.

Answer 1

First problem.

Call a and b the sides. Since the sides are doubled they are 2*a and 2*b

You know the area is given by a*b.

2a*2b = 12

4ab = 12

So divide both terms for 4 :)

ab = 3 ft^2

Second problem.

Find the volume of the two solids.

The first contenitor is a parallelepiped.

V = abh

a = 10
b = 5
h = 6

V = 10*5*6 = 300 in^3

The second solid is a cilinder.

V = pi*r^2*h = 3^2*10*pi = 9*10*pi = 90pi in^3 = 90*3,14 = 282,6 in^3

The first contenitor hold more ice cream