The coordinate of point V is at (-16, 9)
If Point T(-9,5) lies on the perpendicular bisector of UV, this means that the point divides the line UV into two equal parts
Given the following coordinates
Midpoint T = (-9, 5)
U = (-2, 1)
Required
coordinate of point V
Using the midpoint formulas;
Get the value if x₂ and y₂
Similarly;
Hence the coordinate of point V is at (-16, 9)
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The quadrant that the graph will not go through is the second quadrant.
The reason is that the slope is positive and there was a translation 6 units down
<h3>How to know the quadrant the graph will not pass</h3>The quadrants are named in anticlockwise direction starting from the first which has x - positive and y - positive
The graph of y = 2x/3 is a graph with positive slope, moving through the third and first quadrant.
y = 2x/3 - 6 means a translation 6 units down and this pushed the line to get to the fourth quadrant
Hence the remaining quadrant that is untouched is the second quadrant
The graph is attached
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