Answer:
The values of the angles are;
m∠DEA = 62°, m∠ADB = 45°
Step-by-step explanation:
Specify an arc or an angle three letters
Angle opposite an arc on the circumference
m DA ≅ m CB = 62° (Arc between parallel lines are congruent)
∠CAB = 1/2 × m CB = 1/2 × 62° = 31° (Angle at the center = 2 × Angle st the circumference)
∠DBA = 31° (Angle at the center m DA = 2 × Angle st the circumference)
m∠DAB = 104° (Given)
∠ADB = 180° - m∠DAB - ∠DBA = 180° - 104° - 31° = 45° (Interior angles of triangle ΔADB
m∠ADB = 45°
∠AEB = 180 - ∠CAB - ∠DBA = 180° - 31° - 31° = 118°
∠AEB ≅ ∠COD (Vertically opposite angles)
∠DEA ≅ ∠CEB (Vertically opposite angles)
∠AEB + ∠COD + ∠DEA + ∠CEB = 360° (Sum of angles at a point)
118° + 118° + ∠DEA + ∠CEB = 360°
∠DEA + ∠CEB = 360° - 118° - 118° = 124°
Given that ∠DEA = ∠CEB we have;
2 × ∠DEA = 124°
∠DEA = 124°/2 = 62°
m∠DEA = 62°.
